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klemol [59]
3 years ago
7

15a2-6ab-8a2 - 5ab + 20+ a? - ab - 31 -

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0
-12ab+7a power of 2 +a 11
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How do I know when to multiply divide subtract or add
Pani-rosa [81]
PEMDAS is very helpful to remember when thinking of order of operations. Parentheses, Exponents, Multiply, Divide, Add, then Subtract. Always in that order. 

If you are talking about something more specific you may want to give a bit more information.
4 0
3 years ago
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Grandfath
Anestetic [448]

Answer:

11

Step-by-step explanation:

First, write an equation to represent the situation.

34 = 2a + 12

This equation works because your combined age is half of 68, so 34. If your age is a, then yours sister's age is a + 12. if you add your age to your sister's, you get 2a + 12.

Now just solve for a.

34 = 2a + 12

First, subtract 12 from both sides.

22 = 2a

Then divide both sides by 2.

11 = a

So you are 11 years old. If you need to check your work, your age (11) plus your sister's age (11 + 12, which is 23) is 34, which is half of your grandfather's age.

5 0
2 years ago
Using sin^2x+ cos^2 x=1 and other trig properties, simplify the following: (cos^2Ø*tan^2Ø)/(1-cos^2 Ø.
user100 [1]
\dfrac{\cos^2\O\cdot\tan^2\O}{1-\cos^2\O}=\dfrac{\cos^2\O\cdot\tan^2\O}{\sin^2\O}=\dfrac{\cos^2\O}{\sin^2\O}\cdot\tan^2\O\\\\=\dfrac{1}{\dfrac{\sin^2\O}{\cos^2\O}}\cdot\tan^2\O=\dfrac{1}{\left(\dfrac{\sin\O}{\cos\O}\right)^2}\cdot\tan^2\O=\dfrac{1}{\tan^2\O}\cdot\tan^2\O\\\\=\dfrac{\tan^2\O}{\tan^2\O}=1

Used:\\\\\sin^2\O+\cos^2\O=1\to1-\cos^2\O=\sin^2\O\\\\\tan\O=\dfrac{\sin\O}{\cos\O}

8 0
3 years ago
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The price of an item has been reduced by 45% the original price was $95​
Korvikt [17]

Answer:

$42.75

Step-by-step explanation:

you divide 45 by 100 which is .45 then you multiply .45 by 95

4 0
3 years ago
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Please help me with my math please.?
Lady_Fox [76]

Answer:

x = 6, y = 0, m = -1
y = mx + b
0 = -1(6) + b
0 = -6 + b
6 = b
y = -1x + (6)

Step-by-step explanation:

^^^
See answer, pretty simple.

4 0
2 years ago
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