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goldfiish [28.3K]

3 years ago

10

Does anyone know the answer to this

2 answers:

VLD [36.1K]3 years ago

6 0

I believe this is a good definition. I know sign lenguage, this seems reasonable and right.

Delvig [45]3 years ago

5 0

D
is your answer hope this helped

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In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

5 0

3 years ago

PLEASE HELP ASAP!!!!!!

Natali5045456 [20]

Answer:

13.60 See the note below.

Step-by-step explanation:

Remark

This is just the reverse of the question you just did. This time you are trying to solve for c

Givens

a = 8
b = 11
c = ??

Solution

c^2 = a^2 + b^2 Substitute the givens.

c^2 = 8^2 + 11^2 Expand

c^2 = 64 + 121 Combine the right side by adding

c^2 = 185 Take the square root of both sides.

sqrt(c^2) = sqrt(185) Complete the operation

c = 13.601 Round to the nearest 1/100 th

c = 13.60 Note: the zero must be there or the answer does not show the nearest 1/100 th

8 0

3 years ago

Find the solution set to the inequality.<br><br> 4x - 1 < 11

Lemur [1.5K]

4x - 1 < 11
Add 1 to both sides
4x < 12
Divide both sides by 4
x < 3
x is less than 3

4 0

3 years ago

Read 2 more answers

A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

2 years ago

Find area and perimeter of shaded regions below

aleksandrvk [35]

Answer:

Step-by-step explanation:

ABCD is a square.

side = 24 cm

Area of square = side * side = 24 * 24 = 576 cm²

Semicircle:

d = 24 cm

r = 24/2 = 12 cm

Area of semi circle =πr²

= 3.14 * 12 * 12

= 452.16 cm²

Area of shaded region = area of square - area of semicircle + area of semicircle

= 576 - 452.16 + 452.16

= 576 cm²

Perimeter:

Circumference of semicircle = 2πr

= 2 * 3.14 * 12

= 75.36

Perimeter = 2* circumference of semicircle + 24 + 24

= 2 * 75.36 + 24 + 24

= 150.72 + 24 + 24

= 198.72 cm

6 0

3 years ago