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valentinak56 [21]
3 years ago
14

 A nickle is tossed and a dice rolls a 4. Considering that these are independent events, find the probability of getting a head

and rolling a 4.​
Mathematics
1 answer:
Kryger [21]3 years ago
3 0

Answer:

Probability of nickle getting a head: 1/2

Probability of a dice rolling to a  four: 1/6

<h2>Probability of both of them happening: 1/12</h2>

Step-by-step explanation:

Since a nickle has two sides, getting a head would be one in two sides. (1/2)

Since a dice has 6 numbers, rolling a four would be one in six numbers. (1/6)

To have the probability of both of them happening: simply multiply 1/2 and 1/6 (1/12)

If directions are unclear, ask me in the comments.

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The total cost could be $36

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6 is less than 8

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Volume cylinder pi 3.14 d=12 cm h = 6cm d=2r
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678.24cm³

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8 0
3 years ago
Can someone PLEASE help me with Trigonometry???
Svetach [21]
\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\&#10;-------------------------------\\\\&#10;sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}&#10;\\\\\\&#10;sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)&#10;\\\\\\&#10;\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}

but anyway, the numerator will give the angles, and θ is just half of each

\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\&#10;-------------------------------\\\\&#10;sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}&#10;\\\\\\&#10;sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o&#10;\\\\\\&#10;\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

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and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
7 0
3 years ago
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