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valentinak56 [21]
3 years ago
14

 A nickle is tossed and a dice rolls a 4. Considering that these are independent events, find the probability of getting a head

and rolling a 4.​
Mathematics
1 answer:
Kryger [21]3 years ago
3 0

Answer:

Probability of nickle getting a head: 1/2

Probability of a dice rolling to a  four: 1/6

<h2>Probability of both of them happening: 1/12</h2>

Step-by-step explanation:

Since a nickle has two sides, getting a head would be one in two sides. (1/2)

Since a dice has 6 numbers, rolling a four would be one in six numbers. (1/6)

To have the probability of both of them happening: simply multiply 1/2 and 1/6 (1/12)

If directions are unclear, ask me in the comments.

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solniwko [45]

Answer:

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7 0
3 years ago
Is x + 3 a factor of P(x) = x³ - 5x² + 3x + 9 ? Explain.​
Ksju [112]

Answer:

no

Step-by-step explanation:

using the Factor theorem.

If (x + h) is a factor of f(x) then f(- h) = 0

for factor (x + 3) then evaluate P(- 3)

P(- 3) = (- 3)³ - 5(- 3)² + 3(- 3) + 9 = - 27 - 45 - 9 + 9 = - 72

since f(- 3) ≠ 0 then (x + 3) is not a factor of P(x)

4 0
2 years ago
Solve for p<br>6 = 3 + 3p<br>P=​
garik1379 [7]

Answer:

1

Step-by-step explanation:

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6-3=3p

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7 0
3 years ago
Read 2 more answers
Find the 6th term of a geometric sequence with t1=5 and r = -1/2
Hoochie [10]
In this item, we are to calculated for the 6th term of the geometric sequence given the initial value and the common ratio. This can be calculated through the equation,
   
                 An = (A₀)(r)ⁿ ⁻ ¹ 
where An is the nth term, A₀ is the first term (in this item is referred to as t₀), r is the common ratio, and n is the number of terms. 

Substitute the known values to the equation,

                   An = (5)(-1/2)⁶ ⁻ ¹
                   An = -5/32

Hence, the answer to this item is the third choice, -5/32. 
5 0
3 years ago
In your BIO 111 course, you learn that human hair can vary in diameter, but one estimate of the average diameter is 50 microns o
Dafna11 [192]

Answer:

5000 particles of size 10 nanometer should be stacked

Step-by-step explanation:

Average diameter of the of the human hair = 50 micron = 50 × 10⁻⁶ m

Now,

let the number of 10 nanometer i.e 10 × 10⁻⁹ m particle be 'n'

thus,

n × 10 × 10⁻⁹ m = 50 × 10⁻⁶ m

Therefore to find the number of 10 nanometer i.e 10 × 10⁻⁹ m particle,

n = \frac{50\times10^{-6}}{10\times10^{-9}}

or

n = 5000

Hence,

5000 particles of size 10 nanometer should be stacked

4 0
3 years ago
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