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emmainna [20.7K]
2 years ago
7

The diameter of a proton is about 1.9 cross times 10 to the power of short dash 15 end exponent meters. A hydrogen atom has an o

verall length of 100,000 times (or 1 cross times 10 to the power of 5 times) the diameter of a proton.
What is the length of the hydrogen atom, in meters, if it were written in scientific notation?

A. 1.9 x 10 (15 exponent)
B. 1.9 x 10 (-15 exponent)
C. 1.9 x 10 (-8 exponent)
D. 1.9 x 10 (-12 exponent)
Mathematics
1 answer:
tresset_1 [31]2 years ago
5 0

Using scientific notation, the measure is given as follows:

1.9 \times 10^{-10}

<h3>What is scientific notation?</h3>

A number in scientific notation is given by:

a \times 10^b

With the base being a \in [1, 10).

The diameter of a proton, in scientific notation, is given by:

1.9 \times 10^{-15}.

The hydrogen atom has an overall length of 100,000 = 10^5 times the diameter of the proton, hence the length is given by:

L = 100000 \times 1.9 \times 10^{-15} = 10^5 \times 1.9 \times 10^{-15} = 1.9 \times 10^{5 - 15} = 1.9 \times 10^{-10}

For the above length, I applied the multiplication of factors with the same base and different exponents, where we keep the base and add the exponents.

More can be learned about scientific notation at brainly.com/question/16394306

#SPJ1

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raketka [301]

Answer:

x=-4

Step-by-step explanation:

X needs to be a number that when 3 is added to it, becomes -1. So, adding 3 to -4 gives you -1, therefore, x=-4. Hope this helped!

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3 years ago
I WILL GIVE BRAINLIST
GrogVix [38]

Answer:

3,406.5 litres/hr

Step-by-step explanation:

The liquid is being poured at a rate of 15 gallons per minute.

1 minute = 1/60 hour

Thus, the rate can be written as:

15 gallons pet 1/60 hour

We are told that one gallon is approximately 3.785 liters.

Thus;

15 gallons = 15 × 3.785 litres = 56.775 litres.

Thus, the rate is;

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4 0
3 years ago
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

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3 years ago
What is the algebraic solution to the function 2x+3=83
nirvana33 [79]
3-83= 80
80 divided by 2 is 40
the answer is 40
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3 years ago
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Answer:

662.433221

Step-by-step explanation:

907.07 × 1.09 × 0.67

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