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BartSMP [9]
1 year ago
11

MATRECIES: Suppose ={u,v,w}⊆R3 is linearly independent. Determine if the set 4 ={u, v, v−w, u+v+w} is linearly independent or li

nearly dependent.
Mathematics
1 answer:
AlladinOne [14]1 year ago
3 0

The set is linearly dependent.

To explicitly prove this, we need to show there is at least one choice of constants c_1,c_2,c_3,c_3\in\Bbb R such that

c_1 u + c_2 v + c_3(v-w) + c_4(u+v+w) = 0

or equivalently,

(c_1 + c_4) u + (c_2 + c_3 + c_4) v + (-c_3 + c_4) w = 0

which is the same as solving the system of equations

\begin{cases} c_1 + c_4 = 0 \\ c_2 + c_3 + c_4 = 0 \\ -c_3 + c_4 = 0 \end{cases}

From the first and last equations, we have c_1=-c_4 and c_3=c_4. Substituting these into the second equation leaves us with c_2-2c_1=0, and so the overall solution set is

c_1 = \dfrac12 c_2 = -c_3 = -c_4

for which there are infinitely many not-all-zero solutions.

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<h2>A) y = -5x - 8</h2>

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Mr. Clark traveled 456.4 km in 14 days.
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\qquad \qquad\huge \underline{\boxed{\sf Answer}}

<h3><u>Distance travelled each day is</u> : </h3>

  • 32.6 km

<h3><u>Explanation</u> : </h3>

Distance travelled in 14 days is : 456.4 km

And if he travels same Distance each day, so let the Distance travelled on each day be x

According to question ~

\qquad \sf  \dashrightarrow \: 14 \times x = 456.4

\qquad \sf  \dashrightarrow \: x = 456.4 \div 14

\qquad \sf  \dashrightarrow x = \: 32.6  \: \: km

So, he travels 32.6 km per day

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2 years ago
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