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aleksley [76]
3 years ago
5

A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the

function h(t) = − 16t2 + 25t + 3. Show your work.
19. After how many seconds will the balloon hit the ground? (hint: Use the quadratic formula)

20. What will the height be at t = 1 second
Mathematics
2 answers:
sammy [17]3 years ago
7 0
19. The balloon hits the ground means -16t2+25t+3=0
After you solve the equation, there are 2 solution ~1.67 or ~-0.11 (the time can not be negative) so the solution is 1.67s
20.substitute t=1 to the function -16(1)2+25(1)+3=-16+25+3=12 ft. So the height is 12ft when t=1
Komok [63]3 years ago
6 0

Step-by-step explanation:

Given that,

A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the function as :

h(t)=-16t^2+25t+3...................(1)

(a) we need to find the time when the balloon hits the ground. When it hits the ground h(t) = 0

-16t^2+25t+3=0  

Using above equation we get the value of t, t = 1.674 seconds

So, after 1.674 seconds the balloon hits the ground.

(b) We need to find the height at t = 1 seconds. Put the value of t = 1 seconds in equation (1) as :

h(1)=-16(1)^2+25(1)+3

h = 12 feet

So, at t = 1 seconds the height of the balloon is 12 feets.

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