A/B : 4/9 = 12/B
cross multiply
(4)(B) = (9)(12)
4B = 108
B = 108/4
B = 27
P = 4a...where a is the length of one side
P = 4(27)
P = 108 yds <=== perimeter of square B
Answer:
The area is:

Step-by-step explanation:
To find the area of a rectangle, multiply the width by the height (I'll be using x for b, as it is easier when writing the equations):

Answer:
LCM = 20, GCF = 9
Step-by-step explanation:
The formula would be
A=p (1-r)^t
P 3400
R 0.02
Since it decreases every 20 years
From 2000 to 2040 it decreases 2 times so
T 2
A=3,400×(1−0.02)^(2)
A=3,265
It's c
From the information given, we can see that the mass of Iodine-131 halves about every 8 days. There are 3 sets of 8 days in 24 days, so we will need to halve the mass of the sample 3 times:
50÷2=25
25÷2=12.5
12.5÷2=6.25
So after 24 days, the Iodine-131 sample will be 6.25g.
Here's a formula to figure this out, when dealing with bigger numbers:

Where
a = final amount
i = initial amount
1/2 is used because we are dealing with half lifes
t = time
h = half life of the isotope