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masya89 [10]
10 months ago
10

19. in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index posi

tion 0. a. true b. false
Computers and Technology
1 answer:
ICE Princess25 [194]10 months ago
6 0

It is true that in the array implementation of a queue, the pop operation is most efficient if the front of the queue is fixed at index position. The correct option is a.

<h3>What is pop operation? </h3>

The removal of an element is referred to as a pop operation. Again, because we only have access to the element at the top of the stack, we can only remove one element. We simply take the top of the stack off.

A push operation decrements the pointer before copying data to the stack; a pop operation copies data from the stack before incrementing the pointer.

The pop operation in an array implementation of a queue is most efficient if the queue's front is fixed at index position.

Thus, the correct option is a.

For more details regarding pop operation, visit:

brainly.com/question/15172555

#SPJ1

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Write the pseudocode for a program that will process attendance records of CA students. The students attend college five days a
Alenkasestr [34]

Using the knowledge of pseudocodes it will be possible to write a code that calculates the amount of hours worked and giving warnings about it.

<h3>Writing a pseudocode we have that:</h3>

<em>while </em>

<em>if number == 0</em>

<em>break</em>

<em>hours =0 </em>

<em>for i =1 to 5 </em>

<em>hours = hours + time_out[ i ] - time_in[ i ]</em>

<em> If hours >36 : </em>

<em>print ( "Name is " ,name)</em>

<em>print( "No of hours are ",hours)</em>

<em>print("Congratulaion! Your working hours are more than 36")</em>

<em>If hours <30 : #</em>

<em>print ( "Name is " ,name)</em>

<em>print( "No of hours are ",hours)</em>

<em>print("Warning !!!")</em>

<em>End loop</em>

See more about pseudocode at brainly.com/question/13208346

#SPJ1

3 0
1 year ago
Plzz help will mark brainliest
vlabodo [156]

Answer:

11. 3 dimensions

12. ( i believe its number 3)

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7 0
3 years ago
Write a function that returns a chessboard pattern ("B" for black squares, "W" for white squares). The function takes a number N
Kryger [21]

Answer:

Here is the C++ program.

#include <iostream>  //to use input output functions

using namespace std;  // to access objects like cin cout

 

void chessboard(int N){  // function that takes a number N as parameter generates corresponding board

   int i, j;  

   string black = "B";  // B for black squares

   string white = "W"; // W for white squares

   for(i=1;i<=N;i++){  //iterates through each column of the board

       for(j=1;j<=N;j++){  //iterates through each row of the board

           if((i+j)%2==0)  // if sum of i and j is completely divisible by 2

               cout<<black<<" ";  //displays B when above if condition is true

           else  //if (i+j)%2 is not equal to 0

           cout<<white<<" ";  }  // displays W when above if condition is false

      cout<<endl;    }    }  //prints the new line

       

int main(){    //start of the main function

   int num;  //declares an integer num

   cout << "Enter an integer representing the size of the chessboard: ";  //prompts user to enter size of chess board

   cin >> num;  //reads value of num from user

   chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop  for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

8 0
2 years ago
Which type of navigation involves multiple frames that are linked to a number of other frames?
sesenic [268]

Answer:

1. b)

2. c)

3. c)

4. a)

5. b)

Explanation:

1. and 5. Linear kind of navigation is a system with a sequential manner web pages that are perfect for some sorts of sites that are having information that has to be viewed as a book (5) and when we are talking about that view we are considering one page after another page like we are reading a book. It is also the simplest navigation. This is the explanation for question 1 and question 5.

2. The most well-designed navigation system is an intuitive one because in this design of the website we have website traffic that is easy because it flows from one web page to another web page. It is showing us where to go to find and look for something and even where to go if there is no concrete options for what are we looking for.

3. A Sitemap is referring to the organized hierarchy of links and it is the protocol that is allowing us to search through many links. A Sitemap is having a listing of the URLs for some site and that is why this is the correct answer.

4. In using liner reciprocal navigation the interface should include how frames are left and how many of them are there. The more the frames, the more times the user will spend on them and the site.

8 0
2 years ago
What two technologies below are hybrid processors that can handle 32 bit and 64 bit operating systems natively?
Vitek1552 [10]
For the answer to the question above asking <span>What two technologies below are hybrid processors that can handle 32 bit and 64 bit operating systems natively?
I believe the answer here is Intel and AMD (Advance Micro Devices)
I hope my answer helped you.</span>
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