Answer:
umm let me check if my answer is right
Explanation:
Answer:
(Assuming Java)
public ArrayList diff(ArrayList list1, ArrayList list2) {
ArrayList<Integer> union = new ArrayList<>();
for (int element : list1) {
union.add(element);
}
for (int element : list2){
if (!union.contains(element)) {
union.add(element);
}
}
return union;
}
Explanation:
Create an ArrayList that has the union of list1 and list2.
First for loop copies all elements into the union array list.
Second for loop adds all elements that are not yet in the union arraylist to the union arraylist.
(Keep in mind that I assume that you mean a mathematical union, so no duplicates. If this is not what you mean, remove the if statement in the second for loop)
Answer:
The correct answer to the following question will be Option D (a worm).
Explanation:
A PC worm seems to be a form of harmful, self-replicating software that often infects other machines while remaining onto corrupted devices.
- Worms may often go overlooked before their excessive propagation cycle utilizes machine resources, stopping the encrypted file as well as slowing it down.
- The virus is quickly spreading inside the company's servers leading the server or computer to fail.
The other three options are not related to the given scenario. So that Option D is the right answer.