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pantera1 [17]
2 years ago
11

What is technology?

Computers and Technology
1 answer:
Anestetic [448]2 years ago
5 0
D. the application of scientific discoveries 
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PLEASE HELP!!!
mezya [45]

Answer:

I'm not exactly sure on what the question is, but from reading it, I determined that you'll be creating 2 different designs using Inkscape/Photoshop. I'm leaving 2 of my designs in here for you to use on your project. Unknown on what to do about the design that wasn't created in an image-editing program.

4 0
3 years ago
Place the steps in order for inserting an index in a document.
tester [92]

Answer:

Steps to insert an index in a document

Explanation:

  1. open the document
  2. click on the <u>references</u> tab either above or below the document
  3. click the <u>mark entry</u> button
  4. select a word or group of words for the index
  5. click on the <u>mark entry</u> dialogue box
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7 0
3 years ago
Read 2 more answers
Rewrite the following condition to avoid a possible arithmetic exception:
dangina [55]

Answer:

if (x > 7 && Math.sqrt(x) < 3)

Explanation:

The previous condition checks if the square root of x is less than 3, but this would raise an error if x is a value equal to or less than 0.

So, the condition checks for the value of x before evaluating the square root after the AND operation to prevent an arithmetic exception.

4 0
2 years ago
Pete would like to respond only to users within his organization with an automatic reply. He is configuring the automatic respon
Ahat [919]

Answer:

megan pete

Explanation:lol just  had to

4 0
2 years ago
To reduce the number of used digital outputs of the microcontroller, the display board is connected to the main board through th
Luda [366]

Answer:

The program in Python is as follows:

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

num = input("Decimal: ")

BCDValue = ""

valid = True

for i in range(len(num)):

   if num[i].isdigit():

       if(int(num[i])>= 0 and int(num[i])<8):

           BCDValue += BCD[i]+" "

       else:

           valid = False

           break;

   else:

       valid = False

       break;

if(valid):

   print(BCDValue)

else:

   print("Invalid")

Explanation:

This initializes the BCD corresponding value of the decimal number to a list

BCD = ["0001","0010","0011","0100","0101","0110","0111"]

This gets input for a decimal number

num = input("Decimal: ")

This initializes the required output (i.e. BCD value)  to an empty string

BCDValue = ""

This initializes valid input to True (Boolean)

valid = True

This iterates through the input string

for i in range(len(num)):

This checks if each character of the string is a number

   if num[i].isdigit():

If yes, it checks if the number ranges from 0 to 7 (inclusive)

       if(int(num[i])>= 0 and int(num[i])<8):

If yes, the corresponding BCD value is calculated

           BCDValue += BCD[i]+" "

       else:

If otherwise, then the input string is invalid and the loop is exited

<em>            valid = False</em>

<em>            break;</em>

If otherwise, then the input string is invalid and the loop is exited

<em>    else:</em>

<em>        valid = False</em>

<em>        break;</em>

If valid is True, then the BCD value is printed

<em>if(valid):</em>

<em>    print(BCDValue)</em>

If otherwise, it prints Invalid

<em>else:</em>

<em>    print("Invalid")</em>

7 0
3 years ago
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