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marin [14]
1 year ago
14

Solve 3x + 23 + x = 7. x = −4 x = 4 x = −0.25 x = 0.25

Mathematics
1 answer:
Maksim231197 [3]1 year ago
3 0
<h2>______________________________</h2><h2>Solve for x | Solution and Explanation </h2>

______________________________________________

Hello! So...

We are given the following:

Solve for x.

3x+23+x=7

====================

1. Group the like terms.

  • 3x+x+23=7

====================

2. Add similar elements (3x+x=4x).

  • 4x+23=7

====================

3. Subtract 23 from both sides.

  • 4x + 23 - 23 = 7 - 23

====================

4. Simplify.

  • 4x=-16

====================

5. Divide both sides by 4.

  • \frac{4x}{4} =\frac{-16}{4}

====================

6. Simplify.

  • x=-4 (aka. Option A)

====================

Hope this helps!

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Step-by-step explanation:

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Richard cut his pizza into 12 slices. Gianni cut his pizza into 6 slices, and ate 2 slices. Together, ate 9/12 of one pizza. How
andrew11 [14]
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Subtract 9/12 by 4/12

You get 5/12



That means 5/12 must be your answer

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(Answer also can be 5)

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Furkat [3]

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Step-by-step explanation:

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​(0​,0​), ​(1​,3​), ​(2​,24​), ​(3​,81​), ​(4​,192​)

We are asked to find the function or rule connecting x and y

On seeing the pair, first let us find y/x


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7 0
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Learn with an example<br> Find the instantaneous rate of change of k(x) = x at x = 9.
Mrac [35]

Answer:

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Step-by-step explanation:

The expression k(x) = x is equivalent to k(x) = x^{1}.

Apply the power rule of differentiation. For any constant a:

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\begin{aligned}k^{\prime}(x) &= \frac{d}{dx}[x^{1}] \\ &= 1\, x^{1 - 1} \\ &= x^{0} \\ &= 1 && \text{given that $x \ne 0$}\end{aligned}.

In other words, the instantaneous rate of change of k(x) (with respect to x) is constantly 1 at all x \ne 0.

Therefore, for x = 9, instantaneous rate of change of k(x) (with respect to x) would be 1.

4 0
3 years ago
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