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cricket20 [7]
3 years ago
11

If you have one box of eggs and multiply you amount of boxes by 3, how much eggs will you have?

Mathematics
1 answer:
swat323 years ago
4 0

Answer:

You''ll have 3 boxes of eggs.

Step-by-step explanation:

1 x 3 = 3

It depends on how many eggs are in the box. If there were a dozen eggs then that would be thirty six.

I hope this helps!

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Use the drop-down menus to complete the statements. in order for f–1(x) to be a function, the domain of f(x) can be restricted t
zmey [24]

Using concepts of the inverse function, it is found that:

The domain of f(x) has to be restricted to x >= 1. Under this restriction, the domain of f-1(x), would be (2,∞), having the same minimum value as the original function f(x).

<h3>How to find the inverse of an equation or a function?</h3>

To find the inverse, we have to exchange x and y and then isolate y. This can only happen if the function f(x) is injective, that is, each value of the output is related to only one value of the input. Then:

  • The domain of f(x) is the range of the inverse function f-1(x).
  • The range of f(x) is the domain of the inverse function f-1(x).

Researching this problem on the internet, we are given an absolute value function with vertex at x = 1, meaning that for the inverse, the domain of f(x) has to be restricted to x >= 1. The domain of the inverse would be the range of f(x), which is (2,∞).

Then:

The domain of f(x) has to be restricted to x >= 1. Under this restriction, the domain of f-1(x), would be (2,∞), having the same minimum value as the original function f(x).

More can be learned about inverse functions at brainly.com/question/8824268

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6 0
1 year ago
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Lina20 [59]
She can only talk for 400 minutes or 6 hours and 40 minutes
8 0
2 years ago
Name the square root of 18ab and of 3bc​
Dafna11 [192]

Answer:

  1. 6 to th<em>e</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em> </em><em>whereas</em><em>3</em><em>bc</em><em>=</em><em> </em><em>3</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>b</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>c</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>1</em><em>/</em><em>2</em>
8 0
2 years ago
Help please I need to submit soon
den301095 [7]

Step-by-step explanation:

(2.3)^2 +5^2= ?

=6^2 +5^2

= 61

3 0
2 years ago
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