Answer:
question 8: 30975
question 9:
I don't know if it wants me to find the interest from the bond or the quote price of the bond.
If it is the bond it would be $1400 interest.
If it is the quote price of the bond, it would be $1,239 interest.
y= mx+b
(16, -7) = (x,y)
2(16) - 3y = 12
32 - 3y = 12
32 - 12 = 3y
20/3 = y
6.6 = y
2x-3(-7) = 12
2x+21 = 12
2x = 12 - 21
x = -9/2
Insert the values into y = mx + b
solve for m and then solve for b
Dividing by 2, we have S/2=lw+lh+wh. After that, we subtract lh from both sides to get S/2-lh=lw+wh. Next, we divide both sides by w to get (S/2)/w=l+h. Next, we divide by S/2 to get 1/w=(l+h)/(S/2). Lastly, we multiply by w and divide by (l+h)/(S/2) to get w=(S/2)/(l+h)
Answer:
4/3 of an hour, or 1.33 hours
Step-by-step explanation:
It took Mike 1/3 of an hour to mow 1/4 of the yard. This means when it has been 1 full hour, he would have mowed 3/4 of the yard, because
hour. Because of this, we can multiply 1/3 by 4, because he has to mow 4 parts of his lawn, and he can do 1 part in 1/3 of an hour.
hours
Answer:
Kate's possible hourly rate of pay: $34.75
Hours of overtime: 100
Step-by-step explanation:
In order to find Kate's hourly wage, we can set up an equation based on the number of hours she works per week and the estimated number of overtime hours to equal her total pay for the year. If Kate works 36 hours/week and there are 52 weeks in a year, her total hours for one year are: 36 x 52 = 1872. Setting up an equation based on her total earnings of $72,000:
1872x + 100(2x) = 72000, where 'x' is the hourly rate and '2x' is her overtime rate which is double time.
Combine like terms: 1872x + 200x = 72000 or 2072x = 72000
Divide both sides by 2072: 2072x/2072 = 72000/2072
Solve for x: x = $34.75
Kate's hourly rate is estimated at $34.75. We can check to see if this is correct by putting this value back into our original equation:
1872(34.75) + 100(2)(34.75) = 65052 + 6950 = 72002
The answer of $72,002 is very close to $72,000 and the best estimate of Kate's hourly wage and overtime hours.