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skelet666 [1.2K]
3 years ago
5

Steve,Jerry and Ron were paid $29.25 to remove garden gnomes. They each worked 4 hours, exempt for Ron, who was 1 hour late. How

much of the 29.25 should Ron receive?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0
Ron should receive $7.98. Jerry and Steve each worked for 4 hours, while Ron was one hour late, so he worked for 3 hours. Together, they worked for 4*2+3=11 hours, receiving $29.25 in total. Each hour should be paid 29.25/11=2.66 dollars. Ron worked for three hours, so he should receive 3*2.66=7.98 dollars. 
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Type the missing number that makes these fractions equal: 4/?=8/14
ozzi

Answer:

4/7 = 8/14

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1. If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter o
scZoUnD [109]

Answer:

Part 1) The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor (see the explanation)

Part 2) The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) The new figure and the original figure are not similar figures (see the explanation)

Step-by-step explanation:

Part 1) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the perimeter of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its perimeters is equal to the scale factor

so

The perimeter of the new figure must be equal to the perimeter of the original figure multiplied by the scale factor

Part 2) If a scale factor is applied to a figure and all dimensions are changed proportionally, what is the effect on the area of the figure?

we know that

If all dimensions are changed proportionally, then the new figure and the original figure are similar

When two figures are similar, the ratio of its areas is equal to the scale factor squared

so

The area of the new figure must be equal to the area of the original figure multiplied by the scale factor squared

Part 3) What would happen to the perimeter and area of a figure if the dimensions were changed NON-proportionally? For example, if the length of a rectangle was tripled, but the  width did not change? Or if the length was tripled and the width was decreased by a factor of 1/4?​

we know that

If the dimensions were changed NON-proportionally, then the ratio of the corresponding sides of the new figure and the original figure are not proportional

That means

The new figure and the original figure are not similar figures

therefore

Corresponding sides are not proportional and corresponding angles are not congruent

so

<em>A) If the length of a rectangle was tripled, but the  width did not change?</em>

<em>Perimeter</em>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2W ----> P=6L+2W

The perimeter of the new figure is greater than the perimeter of the original figure but are not proportionals

<u>Area</u>

The original area is A=LW

The new area  would be A=(3L)(W) ----> A=3LW

The area of the new figure is three times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

<em>B) If the length was tripled and the width was decreased by a factor of 1/4?</em>

<u>Perimeter</u>

The original perimeter is P=2L+2W

The new perimeter would be P=2(3L)+2(W/4) ----> P=6L+W/2

The perimeter of the new figure and the perimeter of the original figure are not proportionals

<u><em>Area</em></u>

The original area is A=LW

The new area  would be A=(3L)(W/4) ----> A=(3/4)LW

The area of the new figure is three-fourth times the area of the original figure but its ratio is not equal to the scale factor squared, because there is no single scale factor

4 0
3 years ago
Yesterday morning at 8 a.m. the temperature was -14˚F. At noon it was 10 degrees warmer. The temperature increase between noon a
jasenka [17]

8am : -14F

noon : -14+10  = -4F

increase between noon and 4 is 2*10 =20

4 pm: -4F + 20 = 16F

temperature at 4 pm is 16F

8 0
3 years ago
Read 2 more answers
Let ŷ represent the profit (in thousands of dollars) for a certain company x years after 1970. A statistician calculates a linea
Anika [276]

Answer:

$17,280

Step-by-step explanation:

The model for profit (y), in thousands of dollars, as a function of time (x), in years after 1970 is:

y=0.66x +12

The corresponding value of x in 1978 is:

x= 1978-1970\\x=8

Estimating the profit (in thousands of dollars) in 1978:

y(8)=0.66*8 +12\\y(8) = 17.28

Converting it to dollars:

P = \$1,000*y(8)= \$1,000*17.28\\P= \$17,280

The estimated profit in 1978 is $17,280.

5 0
3 years ago
I don’t know the answer please help me out
Masteriza [31]
A. 1/3 x 45 < 45
Explanation:
1/3 x 45 is 15, so the comparison is correct because 15 is less than 45.

the rest of the choices are incorrect because:
B. 60 < 60 x 3/4 is wrong because 60 x 3/4 = 45 which is LESS than 60, not greater

C. 20 x 1/5 >20 is wrong because 20 x 1/5 = 4 which is LESS than 20, not greater

D. 25 < 2/3 x 25 is wrong because 2/3 x 25 = 16 2/3 which is LESS than 25, not greater

Have a nice day (brainliest pls tysm!)
5 0
3 years ago
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