Answer:
We conclude that the calibration point is set too high.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 1000 grams
Sample mean,
= 1001.1 grams
Sample size, n = 50
Alpha, α = 0.05
Population standard deviation, σ = 2.8 grams
First, we design the null and the alternate hypothesis

We use One-tailed(right) z test to perform this hypothesis.
Formula:

Putting all the values, we have

Now, 
Since,

We reject the null hypothesis and accept the alternate hypothesis. We accept the alternate hypothesis. We conclude that the calibration point is set too high.
Answer:
$10.10
Step-by-step explanation:
First we need to convert cm to mm
45 cm = 450 mm
Now our ratio looks like this
60/450
We can divide both by 30 and once we do that our ratio will look like this:
2/15
That means the answer is B
I think X is 2. But I am not sure, cuz I don’t know what you teacher is really asking you to do.
Answer:
y = 18
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
y = 2x + 12
x = 3
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: y = 2(3) + 12
- Multiply: y = 6 + 12
- Add: y = 18