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2 years ago

What is the smallest integer that is above square root of 14?

Mathematics

2 answers:

LenaWriter [7]2 years ago

3 0

Sqrt14 = 3.74165
smallest integer above = 4

kramer2 years ago

3 0

Answer:

3.742 pls mark me branilest pls

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Can someone help me with this?

Elena L [17]

A. Robert purchased a 36-inch piece of wood

3 0

2 years ago

Type the correct answer in each box. Use numerals instead of words.

lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17 eq(1)

y = -1/2x eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a = 5/4, b =0 and c = -17

$x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}$

Finding value of y:

y = -1/2x

$y=-1/2(\frac{\pm2\sqrt{85}}{5})$

$y=\frac{\pm\sqrt{85}}{5}$

System A has 4 real solutions.

System B

y = x^2 -7x + 10 eq(1)

y = -6x + 5 eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-1 and c =5

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}$

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9 eq(1)

8x - y = -17 eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17

8(-2) - y = -17

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0

3 years ago

Read 2 more answers

Help pleaseeeeee!!!!!!!!!!!!!!!

diamong [38]

Answer:

2 meters

Step-by-step explanation:

We need to use trigonometry for this. The appropriate one would be tangent, which is (opposite side) divided by (adjacent side).

In this case, the opposite side of angle A is BC, which is 6 meters. The adjacent side of angle A is AB, which is the ground. Since we don't know its length, we call it x.

Now, we write:

$tan(72)$ = 6/x

To solve, we just multiply both sides by tan(x) and x:

x = 6/[tan(72)] ≈ 1.95 meters ≈ 2 meters.

Thus, the answer is 2 meters.

Hope this helps!

4 0

3 years ago

7. The largest of the Great Pyramids in Egypt was built with a square base,

strojnjashka [21]

Answer:

Difference between the original and current volumes = 4013140.30 cubic feet

Step-by-step explanation:

Largest pyramid has the square base with one edge = 754 feet

Area of the square base = (Side)²

= (754)²

= 568516 square feet

Volume of the pyramid = $\frac{1}{3}(\text{Area of the base})(\text{Height})$

= $\frac{1}{3}\times 568516\times 481$

= 91152065.3 cubic feet

After erosion,

Area of the base = (745)² = 555025 square feet

Volume of the pyramid = $\frac{1}{3}(555025)(471)$

= 87138925 cubic feet

Difference between the original and current volumes of the pyramid

= 91152065.30 - 87138925

= 4013140.30 cubic feet

5 0

3 years ago

Hiiiooo! Can someone please help me if you can’t see the picture I will gladly explain it in the comments!

Neporo4naja [7]

Answer:

Step-by-step explanation:

6 0

3 years ago