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Mathematics

1 answer:

OverLord2011 [107]1 year ago

7 0

Given: a quadratic function with vertex (2,3) opening upward .

Find: the given statement is true or false.

Explanation: if parabola has a vertex at (2,3) and opens upward, it has one real solution., (2,3) will be a lowest point. The vertex will be at lowest point, it will be minimum.

that means graph has no one real solution. hence it will never going to intersect. so this statement is false.

Final answer: the given statement is FALSE.

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How to find the solution of |a-4|=3a-6

Anika [276]

For
|a|=b, solve for
a=b and a=-b

so

|a-4|=3a-6
solve
a-4=3a-6 and a-4=-(3a-6)

first one
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3 years ago

Find the vertex, focus, and directrix. y = 1/24(x+1)² - 3.

Vedmedyk [2.9K]

$y = \frac{1}{24}(x+1)^2 - 3\\\\y+3 =\frac{1}{24}(x+1)^2\ \ / *24\\\\ (x+1)^2 = 24(y+3)$

This is an equation of a parabola that opens upwards.

$Its \ standard \ form: \\(x-h)^2=4p(y-k)\\ (h,k)=(x,y) \ coordinates \ of \ the \ vertex\\\ (h,k)=(-1,-3) \\\\axis \ of \ symmetry: \ x= -1\\ \\4p=24\ \ /:4\\p=6$

$focus:(h,k+p)=(-1,-3+6)=(-1,3) \\ \\directrix: \ y=k-p=-3-6=-9$