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Dovator [93]
3 years ago
5

Can someone please explain this to me please? Thank you : )

Mathematics
1 answer:
Ber [7]3 years ago
6 0

Answer:

7/25

Step-by-step explanation:

if 7% are defective and they order 25% of their lightbulbs from Baker that will be your answer.

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Ryan earns $5 for each small dog he walks and $8 for each large dog he walks. Today he walked 9 dogs and made a total of $51. Ho
Shalnov [3]
Use a system of equations.

(x=# of small dogs, y=# of big dogs)

x+y=9 (times by -5) -5x-5y=-45
5x+8y=51

Then add the equations together and the x's cancel. 

3y=6
y=2

So he walked 2 big dogs and 7 little dogs.
6 0
3 years ago
What is the area if this figure? please help
Kazeer [188]

Answer:

idk

Step-by-step explanation:

5 0
2 years ago
The 4th time of me posting this question
Vanyuwa [196]
Not clear crop it more
3 0
2 years ago
Section 1: Write the following times in 24-hour clock time:
Sav [38]

Answer:

<u>Section 1: </u>

a) 7:15 a.m - 19:15

b) 1:05 am - 01:05

c) 2:01 p.m - 14:01

d) 9:22 p.m - 21:22

e) 12:25 am- 24:25

<u>Section 2: </u>

a) 1155 hours - 11:55am

b) 1005 hours -10:05am

c) 1714 hours - 5:14pm

d) 0756 hours - 7:56am

e) 1345 hours- 1:45pm ​

7 0
3 years ago
Read 2 more answers
An animation has two scenes, each of them being one second long. In the first scene, an object moves along the path p⃗ 1(t)=(−8t
bagirrra123 [75]

Answer: p_{2}(t)=(-8t^{2}+3t-5,7t^{2}+10,8t^{2}+6t+12)

Step-by-step explanation: Velocity is the first derivative of position function, so:

p'_{1}(t)=(-16t+3,14t,16t+6)

Since in the second scene acceleration is zero, velocity must be constant, which means velocity in the second scene is the same as in the first scene, i.e.,

p'_{2}(t)=p'_{1}(t)

p'_{2}(t) = (-16t+3,14t,16t+6)

To determine position function, integrate it:

p_{2}(t) = \int\limits {(-16t+3,14t,16t+6)} \, dt

p_{2}(t) = (-8t^{2}+3t+c_{1},7t^{2}+c_{2},8t^{2}+6t+c_{3})

Now, the "initial condition" is that

p_{2}(0)=p_{1}(1)

p_{2}(0) = (c_{1}c_{2},c_{3})

p_{1}(1)=(-8.1^{2}+3.1,7.1^{2}+3,8.1^{2}+6.1-2)

(c_{1},c_{2},c_{3})=(-5,10,12)

p_{2}(t)=(-8t^{2}+3t-5,7t^{2}+10,8t^{2}+6t+12)

<u>Position function in the second scene is </u>p_{2}(t)=(-8t^{2}+3t-5,7t^{2}+10,8t^{2}+6t+12)<u />

8 0
2 years ago
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