Start on -7 since it is the y intercept(b). 4/1 is the slope. So from seven you would go up 4 right 1.
We are given that the
coordinates of the vertices of the rhombus are:
<span><span>A(-6, 3)
B(-4, 4)
C(-2, 3)
D(-4, 2)
To solve this problem, we must plot this on a graphing paper or graphing
calculator to clearly see the movement of the graph. If we transform this by
doing a counterclockwise rotation, then the result would be:
</span>A(-6, -3)</span>
B(-4, -4)
C(-2, -3)
D(-4, -2)
And the final
transformation is translation by 3 units left and 2 units down. This can still
be clearly solved by actually graphing the plot. The result of this
transformation would be:
<span>A′(6, -8)
B′(7, -6)
C′(6, -4)
D′(5, -6)</span>
2^3 * 2^-5 = 2^(3 + (-5) = 2^(3 - 5) = 2^-2
Answer:
Option B
Step-by-step explanation:
A unit circle means radius of the circle = 1 unit
Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.
Center of the circle is origin (0, 0).
Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = 
OP.Cosθ = 1×Cosθ = 
Cosθ =
θ = 
, 
where n = integers
Similarly, OP×Sinθ = 1×Sinθ = -
Sinθ = -
θ = 
, where n = integer
Common value of θ will be, θ = 
Option B will be the answer.
3x-10+2x=115
5x-10=115
5x=125
x=25
m<b=3(25)-10=65
m<C=2×25=50
