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1 year ago

1/3n-7/12=-3/8 n=5/72 n=-5/72 n=5/8 n=-2 7/8

Mathematics

1 answer:

prisoha [69]1 year ago

3 0

Given the equation;

$\frac{1}{3}n-\frac{7}{12}=-\frac{3}{8}$

To solve, let us multiply through by the least common multiple of the the denominator of the three fractions wich is 24;

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In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin

Mademuasel [1]

Answer: $7\frac{5}{7}$ unit and 18 unit

Step-by-step explanation:

Let ABCD is a trapezoid where AB and CD are the bases. ( In which AB is greatest base which shown in below figure)

AD and BC are the legs of the trapezoid ABCD.

Now, we have ( According to the question ),

AB = 18 unit, BC = 7 unit, AD = 3 unit and DC = 11 unit.

Here the leg AD extends from point D.

Similarly leg BC extends from point C.

Let they meet at point P ( shown in below diagram)

Since In triangles PAB and PDC,

∠PDC ≅ ∠PAB ( because DC ║ AB )

And, ∠ PAB ≅ ∠ PBA

∠DPC ≅ ∠ APB ( reflexive)

Therefore, By AAA similarity postulate,

$\triangle PDC \sim \triangle PAB$

Thus, By the definition of similarity,

$\frac{PD}{PA} = \frac{DC}{AB}$

$\frac{PD}{PD+3} = \frac{11}{18}$ ( because PA = PD+DA)

⇒ 18 PD = 11 PD +33

⇒7PD = 33

⇒ PD = 33/7

Again by the definition of similarity,

$\frac{PC}{PB} = \frac{DC}{AB}$

$\frac{PC}{PC+7} = \frac{11}{18}$ ( because PB = PC + CB)

⇒ 18 PC = 11 PD +77

⇒7PC = 77

⇒ PC = 11

Thus, PA = PD+DA = 33/7 + 3 = $7\frac{5}{7}$

And, PB = PC + CB = 11 + 7 = 18

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3 years ago

Solve for n. n+ 1 = 4(n-8) 0 n = 1 O n = 8 0 n = 11 n = 16 ?

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N=11
I’m not 100% sure
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Answer:

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3 years ago

A soup kitchen makes 15 gallons of soup each day a quarter of the soup is served and the rest is saved for the next day , what i

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Number of ounces left is 1120

Step-by-step explanation:

Step 1: Find number of ounces left after each day.

Given total soup prepared each day = 15 gallons

Amount served each day = 1/4 of 15 = 15/4 gallons

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