Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Y = ln |1 + t - t^3| = (1 - 3t^2)/(1 + t - t^3)
Answer:
Kindly check explanation
Step-by-step explanation:
Given that :
One time fee = $30
Reduced price of ticket after one time fee payment = $17
Regular ticket cost = $25
Write an inequality that can be used to determine the number of reduced price concert tickets you would need to purchase in order for the total cost to be less expensive than the same number of regular tickets
Let the number of tickets needed to purchase = t
Reduced ticket = 30 + 17t
Regular ticket = 25t
30 + 17t < 25t
30 < 25t - 17t
30 < 8t
30/8 < 8t/8
3.75 < t
t > 3.75
Hence number of ticket must be greater than 3.75
t = 4
5x^2 -15x-140
5(x² -(3x) -28)
5(x² +(4x-7x)-28)
5(x(x+4) -7(x+4)
5(x-7)*(x-4)
104 = 10,000 x 1.33 = 13,300