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1 year ago

Chemical Reactions Unit Test

Chemistry

1 answer:

dusya [7]1 year ago

3 0

The right side of the equation yields 3CO₂+6H₂O molecules if the 2 in front of 2O is changed to a 3.

The correct option is A.

<h3>What are molecules ?</h3>

The smallest identifiable unit into which a pure substance can be divided while still retaining its composition and chemical properties is called a molecule.

<h3>Briefing:</h3>

Given the chemical equation expressed as:

CH₄+2O₂ → CO₂ + 2H₂O

According to the equation, 1 mole of methane and 2 moles of oxygen combine to create 1 mole of carbon dioxide and 2 moles of water.

The right equation will be written as: If 3 moles of oxygen are used in place of the original amount of moles of oxygen.

3CH₄+2(3O₂) → 3CO₂ + 6H₂O

This shows that the right side of the equation will result in 3CO₂+6H₂O if the 2 in front of 2O is changed to a 3.

To know more about Molecules visit:

brainly.com/question/19556990

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The complete question is -

Use the equation to answer the question.

CH₄+2O₂ → CO₂ + 2H₂O

If you change the 2 in front of 2O₂ to a 3, what will be the change in the results on the right side of the equation?

A- There are now 3CO₂+6H₂O. molecules.

B- There is an extra O₂ molecule left over.

C- Nothing changes in the equation.

D- There are now 3H₂O molecules.

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Answer:

Multiply the number of moles in the product by the molecular weight of the product to determine the theoretical yield.

Explanation:

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