The answer is B. In order to test something out you need to be able to solve it.
Answer:
a) [A⁻]/[HA] = 0.227
b) [A⁻]/[HA] = 0.991
c) [A⁻]/[HA] = 2.667
Explanation:
In the Henderson-Hasselbalch equation, HA stands from an acid an A⁻ stands from its conjugate base, as follows:
pH = pka + Log [A⁻]/[HA]
pH = 4.874 + Log[CH₃CH₂CO₂⁻]/[CH₃CH₂CO₂H]
4.23 = 4.874 + Log [A⁻]/[HA]
-0.644 = Log [A⁻]/[HA]
= [A⁻]/[HA]
0.227 = [A⁻]/[HA]
4.87 = 4.874 + Log [A⁻]/[HA]
-0.004 = Log [A⁻]/[HA]
= [A⁻]/[HA]
0.991 = [A⁻]/[HA]
5.30 = 4.874 + Log [A⁻]/[HA]
0.426 = Log [A⁻]/[HA]
= [A⁻]/[HA]
2.667 = [A⁻]/[HA]
Answer:
The value of the Golden Igloo is $227.4 million.
Explanation:
First, we need to find the inner and the outer volume of the half-spherical shell:


The total volume is given by:

Where:
: is the inner volume
: is the inner radius = 1.25/2 = 0.625 m
: is the outer volume
: is the outer radius = 1.45/2 = 0.725 m
Then, the total volume of the Igloo is:
![V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}](https://tex.z-dn.net/?f=%20V_%7BT%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20r_%7Bo%7D%5E%7B3%7D%20-%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20r_%7Bi%7D%5E%7B3%7D%20%3D%20%5Cfrac%7B2%7D%7B3%7D%5Cpi%20%5B%280.725%20m%29%5E%7B3%7D%20-%20%280.625%20m%29%5E%7B3%7D%5D%20%3D%200.29%20m%5E%7B3%7D%20)
Now, by using the density we can find the mass of the Igloo:

Finally, the value (V) of the antiquity is:
Therefore, the value of the Golden Igloo is $227.4 million.
I hope it helps you!
Answer:
MgBr(aq) + (NH4)3PO4(aq) -------> NH4Br(aq) + Mg3(PO4)2(s)
Explanation:
Answer:
no, the correct answer is NaCI
Explanation:
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