The number of solutions in the equation is (b) two real solutions
<h3>How to calculate the number and type of solutions?</h3>
The quadratic equation is given as
-5x2 + 4x + 1 = 0.
Rewrite properly as
−5x² + 4x + 1 = 0
The discriminant of a quadratic equation is calculated using
d = b² - 4ac
In the equation −5x² + 4x + 1 = 0, we have
a = -5, b = 4 and c = 1
Substitute a = -5, b = 4 and c = 1 in d = b² - 4ac
So, we have
d = (4)² - 4 * (-5) * (1)
Evaluate
d = 36
Because the discriminant is greater than 0, the equation has two solutions and the type of solution is real solution
Read more about discriminant at
brainly.com/question/17122574
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