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DiKsa [7]
10 months ago
12

What is the opposite? 1) -10 2) -35 3) 124) 100 5) 1 6) X

Mathematics
1 answer:
torisob [31]10 months ago
7 0

Solution

The opposite of a is just -a, taking in count this definition we have this

1) -(-10)=10

2) -(-35)=35

3) -12

4) -100

5) -1

6) -X

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Solve each system of equations <br> 2x- 5y = 7<br> 3x - y = -9
Darina [25.2K]

Answer:

x = -4; y = -3

Step-by-step explanation:

2x - 5y = 7

3x - y = -9

Rewrite top equation. Multiply both sides of bottom equation by -5. Add equations. This eliminates y, and we solve for x.

         2x - 5y = 7

(+)   -15x + 5y = 45

----------------------------

      -13x         = 52

Divide both sides by -13.

x = -4

Substitute -4 for x in the first original equation and solve for y.

2x - 5y = 7

2(-4) - 5y = 7

-8 - 5y = 7

-5y = 15

y = -3

Answer: x = -4; y = -3

-5 =

8 0
3 years ago
A model car is 10 inches long and the actual car that the model replicates is 11 feet 8inches long. what is the scale factor tha
algol13
One over fourteen is your answer
3 0
2 years ago
Andy has 901 cards for a big game if he gives away 789 how much does he have left
Leokris [45]

Answer:

the answer is 112

Step-by-step explanation:

901-789=112

4 0
3 years ago
Breanna works in the mall and her hours increase during busy shopping times of the year. Breanna has a plan to save $25 each wee
vesna_86 [32]
The math I used is probably not the quickest way, but for me, the easiest.
25*5=125  25+20=45  45*7=315  125+315=440  25*4=100  440+100=540  5+7+4=16
B is your answer.
5 0
3 years ago
Read 2 more answers
Which of the following equations will produce the graph shown below?
melisa1 [442]
The graph is a circle, centered at the origin, with radius=4.

We know that we can write the equation of a circle with radius r and center (a,b) as :

                      (x-a)^2+(y-b)^2=r^2.

Thus, substituting (a, b) with (0, 0) and r with 4, we have:

                      x^2+y^2=16.

The solutions of this equation are all the points forming the circle shown in the picture. The solutions of this equation are still the same even if we multiply both sides of the equation by 2, because rewriting the equation as:

x^2+y^2=16\\\\x^2+y^2-16=0\\\\2(x^2+y^2-16)=0, 

we would still have the same roots.

Thus, the equation of the circle can be written as :

                                    2x^2+2y^2=32.


Answer: B

5 0
3 years ago
Read 2 more answers
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