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Oksana_A [137]
3 years ago
12

What's the fraction for 3.20

Mathematics
2 answers:
ss7ja [257]3 years ago
8 0
The fraction for 3.20 is 16/5
Lera25 [3.4K]3 years ago
4 0
Or in simplest form it is 3 1/5
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How many cylindrical can of bottles 12 cm high and with 6 cm diameter could be filled from a tank containing 125 liters of deter
Orlov [11]

Answer:

368 cans.

Step-by-step explanation:

Volume of 1 can = π r^2 h.

Here h (height) = 12 and r (radius) = 1/2 * 6 = 3 cm.

So V =  π * 3^2 * 12

= 108π cm^3.

The tank hold 125 liters

=  125,000 cm^3, so:

Number of cans that could be filled = 125000/ 108 π

= 368.4.

4 0
3 years ago
Read 2 more answers
As part of Kayla's exercise program, she either runs 6 miles/day or rides her bike 10 miles/day. Her new goal is to cover a mini
erik [133]
To determine the number of days, we need to set up equations relating the given values above. The total distance that Kayla would want to travel is a sum of the total distance she traveled from running and the total distance she traveled from biking. So,

200 miles = (6 miles/day) x + (10 miles/day) y

where x is the number of days she spent running and y is the number of days she spent biking.

If the minimum days she used for biking would be 15 days or y = 15, then

200 miles = (6 miles/day) x + (10 miles/day) (15 days)

Solving for x,
200 = 6x + 150
50 = 6x
x = 8.3333 days

Total number of days = 15 days for biking + 8.3333 days for running = 23.3333 days or about 24 days.
8 0
3 years ago
Read 2 more answers
What is 21.035 In expanded form for 5th graders
iragen [17]
20 + 1 + .03 + .005 = 21.035
4 0
3 years ago
Read 2 more answers
‼️‼️any help would be appreciated
never [62]
Because the triangle is equilateral we know that z=60, therefore:

60=\frac{1}{3}x-7
67=\frac{x}{3}
67 \times 3 = x
x=201 <span />
6 0
3 years ago
In ΔNOP, \overline{NP} NP is extended through point P to point Q, \text{m}\angle PNO = (x+14)^{\circ}m∠PNO=(x+14) ∘ , \text{m}\a
adelina 88 [10]

Answer:

<OPQ = 23 degrees

Step-by-step explanation:

Given

Interior angles m∠PNO=(x+14) and m∠NOP=(x−1)

Exterior angle = m<OPQ = (5x-2)

The sum of interior angles is equal to the exterior angle, that is;

m∠PNO+m∠NOP = m<OPQ

x+14 + x-1 = 5x-2

2x + 13 = 5x-2

Collect like terms;

2x-5x = -2-13

-3x = -15

x = 15/3

x = 5

Get <OPQ

<OPQ = 5x - 2

<OPQ = 5(5)- 2

<OPQ = 25-2

<OPQ = 23 degrees

4 0
3 years ago
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