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1 year ago

(a)For an algebra class, all students took a Unit 5 test. Their scores and the amount of hours they studied are contained in the

graph belowa student. A trend line (line of best fit) is given.Time Spent Studying(Hours)a) For the trend line,what is the slope?b) For the trend line,what is the y-intercept?c) Create a slope-intercept equationfor the trend line:

Mathematics

1 answer:

FromTheMoon [43]1 year ago

3 0

$\begin{gathered} x_1=0,y_1=50,x_2=2,y_2=70 \\ a)\text{ }\Rightarrow m=\frac{70-50}{2-0}=10(slope) \\ b)y-50=10(x-0) \\ y-50=10x \\ y=10x+50 \\ Y-\text{intercept is}\Rightarrow50 \\ c)y=10x+50(\text{slope}-\text{intercept equation)} \end{gathered}$

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Answer:

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The missing choices are :

1) The slope of the line is 10

2)One point on the line is (40, 10)

3)The slope of the line is 60

4)One point on the line is (10, 60)

Given the equation y−10=60(x−40), applying distributive property we get:

y−10=60x - 60*40

t = 60x - 2400 + 10

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The slope is the number that multiplies x, that is, 60.

To check if the point (40, 10) belongs to the equation, replace the values x = 40 and y = 10 in the equation, as follows:

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The same number appear at both sides of the equal sign, then the point (40, 10) is on the line. Analogously, for point (10, 60):

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