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2 years ago

7

Match each organ or function with its body system Excretory and digestive are the options

1 answer:

Tresset [83]2 years ago

3 0

Answer:

digestive would be stomach, excretion is the big and small intestines

Step-by-step explanation:

stomach digests food, your intestines process whatever is left till you excrete

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The line defined by the equation 2y+3=-(2/3)(x-3) is tangent to the graph of g(x) at x=-3. What is the value of the limit as x a

Otrada [13]

<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span> $\boxed{ -\frac{1}{3} }$

8 0

2 years ago

The libraries in four counties assess late fees for overdue videos by using linear functions. Each library charges a base amount

Sindrei [870]

Answer:

Cumberland and Lincoln

5 0

3 years ago

Read 2 more answers

Find the value of w to make the statement true.<br>-w = -10 + 4w

Alinara [238K]

Move variable to the left. -w= -10+ 4W
-w-4W =-10
Collect like terms
-5w=-10 divide both sides by 5

8 0

3 years ago

At the car dealership, they keep the ratio

Mashutka [201]

Answer

13 2/9

Step-by-step explanation:

8:3 is the ratio which means that you multiply that (8x3) is 24 - 11 because 2/9/ 2+9 = 11 and 24-11 is 13 so there is your answer

7 0

2 years ago

webassign If a snowball melts so that its surface area decreases at a rate of 6 cm2/min, find the rate at which the diameter dec

drek231 [11]

Answer:

The answer is $\frac{3}{10\pi } cm/min$

Step-by-step explanation:

Assuming the snowball is a perfect sphere, then if A denotes the surface area and D the diameter then:

$A=4\pi r^{2} = 4\pi (\frac{D}{2} )^{2} =\pi D^{2}$

Differentiating wrt r we have:

$\frac{dA}{dD} =2\pi D$

We are told that $\frac{dA}{dt}= -6$ and we want to find $\frac{dD}{dt}$

By the chain rule we have:

$\frac{dA}{dD}=\frac{dA}{dt}.\frac{dt}{dD}=\frac{\frac{dA}{dt} }{\frac{dD}{dt} }$

∴ $2\pi D=-\frac{6}{\frac{dD}{dt} }$

∴ $\frac{dD}{dt}=-\frac{6}{2\pi D}$

When D=10 then

$\frac{dD}{dt} =-\frac{6}{10*2\pi } =-\frac{3}{10\pi }$

The sign (-) shows that the D is decreasing.

3 0

3 years ago