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aleksklad [387]
1 year ago
14

I need help! Please please

Computers and Technology
1 answer:
Scorpion4ik [409]1 year ago
6 0

The correct answers are given as:

  1. Turning the lens dial clockwise
  2. Manual settings
  3. Tone
  4. File format
  5. JPEG or RAW

The given questions had to do with taking photos, photography, and the likes and how lenses are used to capture images, and file formats are used to select the size and quality of images.

<h3>What is Photography?</h3>

This refers to the art of taking pictures in a background in a bid to make still images.

Hence, we can see that The correct answers are given:

  1. Turning the lens dial clockwise
  2. Manual settings
  3. Tone
  4. File format
  5. JPEG or RAW

The given questions had to do with taking photos, photography, and the likes and how lenses are used to capture images, and file formats are used to select the size and quality of images.

Read more about photography here:

brainly.com/question/13600227

#SPJ1

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4 0
4 years ago
Write a program that takes three numbers as input from the user, and prints the largest.
S_A_V [24]

Answer:

In Python:

n1 = int(input("Enter a number: "))

n2 = int(input("Enter a number: "))

n3 = int(input("Enter a number: "))

if n1 >= n2 and n1 >= n3:

   print("Largest: "+str(n1))

elif n2 >= n1 and n2 >= n3:

   print("Largest: "+str(n2))

else:

   print("Largest: "+str(n3))

Explanation:

The next three lines get three numbers from the user

n1 = int(input("Enter a number: "))

n2 = int(input("Enter a number: "))

n3 = int(input("Enter a number: "))

This checks if the first number is greater than the other two. If yes, the first number is printed as the largest

<em>if n1 >= n2 and n1 >= n3:</em>

<em>    print("Largest: "+str(n1))</em>

This checks if the second number is greater than the other two. If yes, the second number is printed as the largest

<em>elif n2 >= n1 and n2 >= n3:</em>

<em>    print("Largest: "+str(n2))</em>

This prints the third number as the largest, if the other two conditions fail

else:

   print("Largest: "+str(n3))

3 0
3 years ago
Read 2 more answers
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