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timurjin [86]
1 year ago
13

Given that A = {1, 2,2 3} and B = {4, 6}, then find B×A

Mathematics
1 answer:
Gre4nikov [31]1 year ago
7 0

The solution for set B × A is {(4, 1), (4, 2), (4, 3), (6, 1), (6, 2), (6, 3)}

Given,

The sets,

A = {1, 2, 3}

B = {4, 6}

We have to find B × A.

Here,

Consider the Cartesian product:

The set of all ordered pairs (x, y) such that x belongs to A and y belongs to B is referred to as the Cartesian Product of sets A and B in mathematics. For instance, the Cartesian Product of A and B is (1, 3), (1, 4), (1, 5), (2, 3), (2, 4), and (2, 5) if A = [1, 2] and B = [3, 4, 5].

The Cartesian product of B × A = {(b, a) | b € B, a € A}

So,

B × A = {4, 6} × {1, 2, 3}

B × A = {(4, 1), (4, 2), (4, 3), (6, 1), (6, 2), (6, 3)}

Learn more about Cartesian product here:

brainly.com/question/24372634

#SPJ1

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A street sign is 8ft 1 inch tall. How tall is it in inches?
xxTIMURxx [149]

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A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than
ruslelena [56]

Answer:

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

Step-by-step explanation:

Cuboid : A cuboid is a three dimension shape. The length ,breadth and height of a cuboid are not same.

  • A cuboid has 6 faces.
  • A cuboid contains 8 vertices.
  • A cuboid contains 12 edges .
  • The total surface area of a cuboid is

           = 2(length×breadth+breadth×height+length×height) square units

  • The dimension of a cuboid is written as length×breadth×height.
  • The volume is( length×breadth×height) cubic units

Given that the volume of the box is 192 cubic inches.

Let x inches be the width of the cuboid.

Since the length is twice as long as its width.

Then length = 2x inches

Again height is 2 inches longer than width.

Then height = (x+2) inches.

Therefore the volume of the cuboid is

=[x\times 2x\times (x+2)]   cubic inches

=[2x^2(x+2)]     cubic inches

=(2x^3+4x^2)     cubic inches

According to the problem,

2x^3+4x^2=192

\Rightarrow 2x^3+4x^2-192=0

\Rightarrow 2(x^3+2x^2-96)=0

\Rightarrow (x^3+2x^2-96)=0

\Rightarrow x^3-4x^2+6x^2-24x+24x-96=0

\Rightarrow x^2(x-4) +6x(x-4)+24(x-4)=0

\Rightarrow (x-4)(x^2+6x+24)=0

Therefore x=4

Since the all zeros of x²+6x+24 =0 is negative.

Therefore breadth = 4 inches

 length=(2×4) inches=8 inches

 and height = (4+2)inches = 6 inches.

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

8 0
3 years ago
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