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NISA [10]
1 year ago
9

The total cost of lunch is $3.50, consisting of a juice, a sandwich, and a pear. The juice cost 1.5 times as much as the pear. T

he sandwich costs $1.40 more than the pear. What is the price of the pear?
Mathematics
1 answer:
vodka [1.7K]1 year ago
3 0

The price of the pear is $0.6

Given:

The total cost of lunch is $3.50, consisting of a juice, a sandwich, and a pear.The juice cost 1.5 times as much as the pear.The sandwich costs $1.40 more than the pear.

From above statements

Juice + sandwich + pear = $3.50      -----------eq(1)

Juice = 1.5 * pear

sandwich = pear + $1.40

substitute juice and sandwich values in eq(1)

1.5 pear + pear + $1.40 + pear = $3.50

3.5 pear = $3.50 - $1.40

pear = $2.10/3.5

pear = $0.60

Hence the price of the pear is $0.6

Learn more about the price and pear here:

brainly.com/question/22237949

#SPJ1

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A circle has a diameter of 14cm Work out the circumference of this circle. Give your answer in terms of 3.14 and state it's unit
Karolina [17]

C = 14π cm ( in terms of π )

the circumference (C) of a circle is calculated using the formula

C = πd ( where d is the diameter )

C = 14π cm ≈ 3.14 × 14 - 43.96 cm


3 0
3 years ago
A company has to buy computers and printers. Each computer, x, costs $585 and each printer, y, costs $385. If the company spends
Luden [163]

The company bought 9 computers and 6 printers

<em><u>Solution:</u></em>

Let "x" be the number of computers bought

Let "y" be the number of printers bought

cost of 1 computer = $ 585

cost of 1 printer = $ 385

<em><u>The company buys a total of 15 machines</u></em>

Therefore, we can frame a equation as:

number of computers bought + number of printers bought = 15

x + y = 15 ------ eqn 1

<em><u>The company spends $7,575</u></em>

Therefore, we can frame a equation as:

number of computers bought x cost of 1 computer + number of printers bought x cost of 1 printer = 7575

x \times 585 + y \times 385 = 7575

585x + 385y = 7575 ------ eqn 1

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

x = 15 - y --------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

585(15 - y) + 385y = 7575

8775 - 585y + 385y = 7575

-200y = 7575 - 8775

-200y = -1200

y = 6

<em><u>Substitute y = 6 in eqn 3</u></em>

x = 15 - 6

x = 9

Thus the company bought 9 computers and 6 printers

6 0
3 years ago
What would the integer 500 equal using powers of 10? How did you come up with that answer?
strojnjashka [21]
Hello,

500=10^x
==> Log 500=xLog10
==>x=log 500
==>x=2,6989700043360188047862611052755...


8 0
2 years ago
Anonymous 3 years ago
scZoUnD [109]
I'm in 7th grade and I need help with my math homework
8 0
3 years ago
Need help me please don't know this
motikmotik

Answer:

c.9

the correct answer

semoga jawapan ini membantu

8 0
2 years ago
Read 2 more answers
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