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NISA [10]
1 year ago
9

The total cost of lunch is $3.50, consisting of a juice, a sandwich, and a pear. The juice cost 1.5 times as much as the pear. T

he sandwich costs $1.40 more than the pear. What is the price of the pear?
Mathematics
1 answer:
vodka [1.7K]1 year ago
3 0

The price of the pear is $0.6

Given:

The total cost of lunch is $3.50, consisting of a juice, a sandwich, and a pear.The juice cost 1.5 times as much as the pear.The sandwich costs $1.40 more than the pear.

From above statements

Juice + sandwich + pear = $3.50      -----------eq(1)

Juice = 1.5 * pear

sandwich = pear + $1.40

substitute juice and sandwich values in eq(1)

1.5 pear + pear + $1.40 + pear = $3.50

3.5 pear = $3.50 - $1.40

pear = $2.10/3.5

pear = $0.60

Hence the price of the pear is $0.6

Learn more about the price and pear here:

brainly.com/question/22237949

#SPJ1

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Answer:

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Step-by-step explanation:

You could set up an expression (2x + 8) * (x + 3), where you multiply 2x by x, 2x by 3, 8 by x, 8 by 3, and then add them all up. 2x * x  = 2x^2, 2x * 3 = 6x, 8 * x = 8x, and 8 * 3 = 24. 2x^2 + 6x + 8x + 24 = 2x^2 + 14x + 24, so that is your answer.

3 0
3 years ago
The polar curve $r = 1 + \cos \theta$ is rotated once around the point with polar coordinates $(2,0).$ What is the area of the r
mash [69]

Answer:

Area = -2.3147

Step-by-step explanation:

Given

$r = 1 + \cos \theta$

Required

Determine the area with coordinates (2,0)

The area is represented as:

Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta

Where

$r = 1 + \cos \theta$

and

(a,b) = (2,0)

Substitute values for r, a and b in

Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta

Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)^2} \, d\theta

Expand

Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)(1 + cos\theta)} \, d\theta

Area = \frac{1}{2}\int\limits^0_2 {(1 + 2cos\theta+cos^2\theta} )\, d\theta

By integratin the above, we get:

Area = \frac{1}{2}*\frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{2}[0,2]

Area = \frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{4}[0,2]

Substitute 0 and 2 for \theta one after the other

Area = \frac{(cos(0) + 4)sin(0) + 3*0}{4} - \frac{(cos(2) + 4)sin(2) + 3*2}{4}

Area = \frac{(cos(0) + 4)sin(0)}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}

Area = \frac{(1 + 4)*0}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}

Area =  - \frac{(cos(2) + 4)sin(2) + 6}{4}

Area =  \frac{-sin(2)(cos(2) + 4) - 6}{4}

Get sin(2) and cos(2) in radians

Area = \frac{-0.9093 * (-0.4161 + 4) - 6}{4}

Area = \frac{-9.2588}{4}

Area = -2.3147

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2 years ago
Population of Summerville is currently 20 hundred people. Write a formula if It grows at a constant rate of 1.5 hundred people p
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5 0
3 years ago
Im confused, help please?
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I think it’s g(0)=0, g(1)=1, and g(-1)=1
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Identify the slope and y-intercept of the line whose equation is given. write the y-intercept as an ordered pair. y = negative 2
PSYCHO15rus [73]

The line having the equation, y = -2x + 5, has a slope = -2, and y-intercept = (0, 5). Thus, <u>option A</u> is the best choice.

The slope of a line is the tangent of the angle that the line makes with the positive side of the x-axis.

The y-intercept of a line is the point at which the line intersects the y-axis.

The standard form of a line is <u>y = mx + b</u>, where m represents the slope of the line, and b represents its y-intercept.

In the question, we are asked to identify the slope and the y-intercept of the line whose equation is y = -2x + 5.

Comparing the given equation of the line, y = -2x + 5, with the standard equation of a line, y = mx + b, we can say that,

m = -2, and b = 5.

Representing b as an ordered pair, we get (0, 5), as b represents the y-intercept which is a point on the y-axis, where the x-coordinate is always equal to zero.

Thus, we get the slope = -2, and the y-intercept = (0, 5).

The option representing the answer is <u>option A</u>.

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