The normal body temperature : to = 37° C
An inequality is:
| t - to | ≤ 3
| t - 37 | ≤ 3
t - 37 ≤ 3 AND ( - t - 37 ) ≤ 3
t ≤ 3 +
37
- t + 37 ≤ 3
t ≤
40
- t ≤ 3 - 37
- t ≤ - 34 / *( - 1 )
t ≥ 34
Answer t <span>∈ [</span><span>
34</span><span>°C,</span><span>
40</span><span>° C ]</span>.
Answer:
the answer is b
Step-by-step explanation:
khan academy
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
2x=12 is an equation with the solution of 6
