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4 years ago

PLS HELP

Mathematics

1 answer:

Sloan [31]4 years ago

5 0

Answer:

8√5 units.

Step-by-step explanation:

See the diagram in the coordinate plane attached.

A rhombus has four equal sides and to find the perimeter of the rhombus we have to measure any of the sides of the figure of the rhombus.

The coordinates of the topmost point are (-1,-1) and that of the rightmost point are (3,-3).

Therefore, side length of the rhombus will be

$\sqrt{(- 1 - 3)^{2} + (- 1 - (- 3))^{2}} = \sqrt{20} = 2\sqrt{5}$ units.

So, the perimeter of the rhombus will be (4 × 2√5) units = 8√5 units. (Answer)

The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ on a coordinate plane is given by

$\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}$

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Expand and simplify: (x + 6)2

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Enter the solution (x, y) to the system of equations shown x = 2.5 5y + 2x = -10

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Answer:

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3 years ago

Read 2 more answers

Use the quadratic formula to find both solutions to the quadratic equation given below.

Tpy6a [65]

The solution of the equation are $x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

<h3>How to determine the solution?</h3>

The equation is given as:

3x^2 - 7x- 1 = 0

The quadratic equation is represented as:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

So, we have:

$x = \frac{7 \pm \sqrt{(-7)^2 - 4 *3 *-1}}{2*3}$

Evaluate the expression

$x = \frac{7 \pm \sqrt{61}}{6}$

Expand

$x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

Hence, the solution of the equation are $x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

Read more about quadratic formula at:

brainly.com/question/1214333

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2 years ago

A Internet provider has implemented a new process for handling customer complaints. Based on a review of customer complaint data

sergey [27]

Answer:

a) The mean time for handling a customer complaint under the new process using 95% confidence level is between 25.0 min. and 27.5 min.

b) there is no substantial evidence (in 95% confidence level) that the new process has reduced the mean time to handle a customer complaint.

c) The population about which inferences from these data can be made is the people following the new implemented plan when handling customer complaints.

Step-by-step explanation:

the random sample of the response times of 50 customers who had complaints has

size=50

mean≈26.218

standard deviation ≈4.42

a. Confidence interval can be estimated using the formula:

M± $\frac{z*s}{\sqrt{N} }$ where

M is the sample mean (26.22)
z is the corresponding z-score for the 95% confidence interval (1.96)
s is the sample standard deviation (4.42)
N is the sample size (50)

When we put the numbers in the formula, mean time for handling a customer complain under the new process using 95% confidence interval is:

26.22± $\frac{1.96*4.42}{\sqrt{50} }$ ≈ 26.22±1.225 i.e. between 25 and 27.45

b. According to the customer complaint data for the past 2 years, the mean time for handling a customer complaint was 27 minutes. After the plan, estimated mean time for handling customer complaint is between 25.0 min. and 27.5 min. with 95% confidence. Since 27 min. is within this interval, we can conclude that there is no substantial evidence (in 95% confidence level) that the new process has reduced the mean time to handle a customer complaint.

c. The population about which inferences from these data can be made is the people following the new implemented plan when handling customer complaints.

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3 years ago