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Mathematics

1 answer:

Sloan [31]3 years ago

5 0

Answer:

8√5 units.

Step-by-step explanation:

See the diagram in the coordinate plane attached.

A rhombus has four equal sides and to find the perimeter of the rhombus we have to measure any of the sides of the figure of the rhombus.

The coordinates of the topmost point are (-1,-1) and that of the rightmost point are (3,-3).

Therefore, side length of the rhombus will be

$\sqrt{(- 1 - 3)^{2} + (- 1 - (- 3))^{2}} = \sqrt{20} = 2\sqrt{5}$ units.

So, the perimeter of the rhombus will be (4 × 2√5) units = 8√5 units. (Answer)

The distance between two points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ on a coordinate plane is given by

$\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}$

You might be interested in

E is the midpoint of DF, DE = 2x + 4, and EF = 3x + 1. Find DE, EF, and DF.

Agata [3.3K]

When there is a midpoint in a line segment, the two segments that are then produced have to be equal. So that means that because E is a midpoint of DF, DE=EF.
Set up the equation.
DE=EF
2x+4=3x+1
Then solve for x.
x=3
Then plug it back in the equation to find DE and EF.
DE=2x+4=2(3)+4=10
Because DE=EF then EF is also 10.
DF is made from the addition of DE and EF so DF is twice EF.
DF= 20

DE= 10, EF= 10, DF= 20

Hope this helps.

8 0

3 years ago

Need help solving this problem

Molodets [167]

Answer:

Step-by-step explanation:

q is TFTF

~q use negation, not q so is the opposite of q : FTFT

p↔~q use biconditional ,and will be True only is both statements are T or both are F

p values are TTFF ↔~q values are FTFT : FTTF

(p↔~q )∧~q use conjunction, that is True only if both statements are T

(p↔~q ) values are FTTF ∧~q values are FTFT : FTFF