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Blizzard [7]
1 year ago
5

Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p

Mathematics
1 answer:
anyanavicka [17]1 year ago
7 0

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

A_{sq}=mp

The area of the triangle is given by the following formula:

A_t=\frac{bh}{2}

Where "b" is the base and "h" is its height. Replacing the values:

A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m

The total area is the sum of both areas:

A=A_{sq}+A_t

replacing the areas:

A=mp+\frac{1}{2}6m

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if a 14 foot tree casts a 8 foot long shadow. how tall is a tree that casts a 4 foot long shadow?
kvasek [131]

7-foot

EXPLANAT

Given:

14 foot tree

8foot shadow

4foot shadow

Let h be the height of a tee that casts a 4 foot long shadow.

Using proportion;

14 foot = 8 ft shadow

h = 4 ft shadow

Cross - multiply

8h = 56

Divide both-side by 8

h = 7 foot.

Hence, the tree is 7-foot.

4 0
1 year ago
Find each missing number 67 subtract B = 16​
ahrayia [7]

Answer:

51

Step-by-step explanation:

67 minus 16 equals 51

3 0
3 years ago
Read 2 more answers
Find the measure of the numbered angle m<2
olya-2409 [2.1K]
130 degrees yuhhhhhhhh
5 0
3 years ago
You have a choice between 2 jobs, one pays $8.25/hr but requires you to spend $20 to get a uniform. The other pays $7.50/hr. At
Veronika [31]

Step-by-step explanation + Answer:

x = 1st job

y = 2nd job

x + y = 22......x = 22 - y

7x + 8.25y = 171.50

7(22 - y ) + 8.25y = 171.50

154 - 7y + 8.25y = 171.50

-7y + 8.25y = 171.50 - 154

1.25y = 17.50

y = 17.50 / 1.25

y = 14 <== 14 hrs at the 8.25 per hr job

x + y = 22

x + 14 = 22

x = 22 - 14

x = 8 <=== 8 hrs at the 7 per hr job

5 0
1 year ago
What is the answer to number 14??
son4ous [18]
Zero has one square root which is 0.
Negative numbers Don't have real aquare roots since a square is either positive or 0. The square roots of numbers that are not a perfect square are members or the irrational numbers. That means that they can't be written as the quotient of two integers.
3 0
3 years ago
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