(A) 5a +10b -36
(B) 19p + 921
(C) -4a +7b
(D) 7x -9y + 10z
Answer:
C.52 square units
Step-by-step explanation:
We are given that
Length of cross-section ADGF,l=13units
Length of cross-section ADGF, b=4 units
We have to find the area of cross-section ADGF of this right rectangular prism.
We know that
Area of rectangle=
Using the formula
Area of cross-section ADGF of this right rectangular prism
=
Area of cross-section ADGF of this right rectangular prism=52square units
Option C is correct.
C.52 square units
Answer:
Segments AB and CD are perpendicular to each other.
Step-by-step explanation:
If you were to convert line segments AB and CD into slope-intercept form(y=mx+b), you would get y=-5x+1 for AB and y=1/5x-5.
Any line with a slope that is flipped-oppisite (-5/1 to -1/5 to1/5)
of another line must be perpendicular to each other. It doesn't have to have the same y-intercept, it just makes the intersecting point different.
Answer:

Step-by-step explanation:
Use the Distance Formula:
![\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = D \\ \\ \sqrt{[6 - 1]^2 + [-7 + 1]^2} = \sqrt{5^2 + [-6]^2} = \sqrt{25 + 36} = \sqrt{61} ≈ 7,810249676 ≈ 8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Csqrt%7B%5B-x_1%20%2B%20x_2%5D%5E2%20%2B%20%5B-y_1%20%2B%20y_2%5D%5E2%7D%20%3D%20D%20%5C%5C%20%5C%5C%20%5Csqrt%7B%5B6%20-%201%5D%5E2%20%2B%20%5B-7%20%2B%201%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%20%5B-6%5D%5E2%7D%20%3D%20%5Csqrt%7B25%20%2B%2036%7D%20%3D%20%5Csqrt%7B61%7D%20%E2%89%88%207%2C810249676%20%E2%89%88%208)
Since we are talking about distance, we ONLY want the NON-NEGATIVE root.
I am joyous to assist you anytime.