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marin [14]
1 year ago
5

Use compatible numbers to estimate the whole number quotients 5320/61?

Mathematics
1 answer:
alexandr402 [8]1 year ago
4 0

The whole number quotients of the expression; 5320/61 as required to be evaluated in the task content is; 88.

<h3>What is the best estimate of the whole number quotients of the expression; 5320/61 as given in the task content?</h3>

It follows from the task content that the use of compatible numbers is to be used to estimate the whole number quotients 5320/61.

On this note, since the numbers can be written as follows;

= (53.2 × 100)/(0.61 × 100)

= 53.2/0.61

The estimate can therefore be determined by evaluating;

= 53/0.6

= 88 remainder 1.

Therefore, the closest estimate of the whole number quotients 5320/61 as given in the task content is; 88.

Ultimately, the whole number quotients of the expression; 5320/61 as required to be evaluated in the task content is; 88.

Read more on quotients;

brainly.com/question/16720439

#SPJ1

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Find the volume of a right circular cone that has a height of 14.3 ft and a base with a diameter of 17.2 ft. Round your answer t
katrin [286]

Answer:

the real answer is 1107.5 ft  

3

Step-by-step explanation:

Volume of Cone:

V=\frac{1}{3}\pi r^2h

V=  

3

1

​  

πr  

2

h

\text{Find radius:}

Find radius:

r=\frac{\text{diameter}}{2}=\frac{17.2}{2}=8.6

r=  

2

diameter

​  

=  

2

17.2

​  

=8.6

h=14.3\hspace{40px}r=8.6

h=14.3r=8.6

Needed information

V=

V=

\,\,\frac{1}{3}\pi r^2h

3

1

​  

πr  

2

h

V=

V=

\,\,\frac{1}{3}\pi (8.6)^2(14.3)

3

1

​  

π(8.6)  

2

(14.3)

Plug in

V=

V=

\,\,1107.54545168

1107.54545168

Evaluate in calculator

V\approx

V≈

\,\,1107.5\text{ ft}^3

1107.5 ft  

3

5 0
3 years ago
Which one of the following is a polynomial with real coefficients that has 2 and. 2-i as zeroes
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Step-by-step explanation:

4 0
3 years ago
4. A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution. How many
solniwko [45]

Given:

A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution.

To find:

The quantity of the 60% solution in the mixture.

Solution:

Let x be the quantity of the 60% solution and y be the quantity of the 21% solution.

Quantity of mixture is 234. So,

x+y=234

x=234-y                  ...(i)

The mixture has 43% fertilizer. So,

\dfrac{60}{100}x+\dfrac{21}{100}y=\dfrac{43}{100}\times 234

Multiply both sides by 100.

60x+21y=10062            ...(ii)

Using (i) and (ii), we get

60(234-y)+21y=10062

14040-60y+21y=10062

-39y=10062-14040

-39y=-3978

Divide both sides by -39.

\dfrac{-39y}{-39}=\dfrac{-3978}{-39}

y=102

Putting this value in (i), we get

x=234-102

x=132

Therefore, 132 liters of the 60% solution must be used.

3 0
3 years ago
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