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saul85 [17]
3 years ago
11

What is one and two thirds times two and three fourths

Mathematics
2 answers:
andrey2020 [161]3 years ago
7 0
The answer is 2 and two twelfths.
dedylja [7]3 years ago
7 0
3 3/4 is your answer
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Solve for n. 2/3(1+n)=-1/2n
notka56 [123]

Answer:

=−4/7

Step-by-step explanation:

And yh I'm sorry if I got it wrong

5 0
3 years ago
13x=-21-6y and -8x=36+6y
IgorLugansk [536]

Answer:

x=3\\y=-10

Step-by-step explanation:

13x=-21-6y\\-8x=36+6y

Let's take one of the equations and solve for x. I'll take the first one.

13x=-21-6y

Divide by 13.

x=\frac{-21-6y}{13}

Now replace x in the second equation.

-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y

Distribute -8

\frac{168+48y}{13}=36+6y

Break down the fraction.

\frac{168}{13}+\frac{48}{13}y=36+6y

Subtract \frac{168}{13}

\frac{48}{13}y=36+6y-\frac{168}{13}

Subtract 6y

\frac{48}{13}y-6y=36-\frac{168}{13}

Combine like terms;

\frac{48-13*6}{13}y=\frac{36*13-168}{13}

Solve;

\frac{48-78}{13}y=\frac{468-168}{13}

Keep solving;

\frac{-30}{13}y=\frac{300}{13}

Multiply by the negative reciprocal of the fraction next to y.

(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

y=-10

After having found y, replace it in any of the equations to find x.

13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3

6 0
3 years ago
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stiks02 [169]
Plug it in

7(4) + 8(5) which would be 28 + 40

Answer: 68
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3 years ago
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The distance between the points (-2, -4) and (3,8) is?
forsale [732]

Answer:

(5,4)

Step-by-step explanation:

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2 years ago
Please help me babes!!
abruzzese [7]
The correct answer would be C) CBA-EFD 
6 0
3 years ago
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