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Drupady [299]
9 months ago
15

Solve 3x^2=-12x-15 using a quadratic equation with complex solutions

Mathematics
1 answer:
adelina 88 [10]9 months ago
5 0

The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

What is Quadratic equation?

An algebraic equation of the second degree is called a quadratic equation.

Given that;

A quadratic equation is;

3x² = -12x - 15

Now, The equation is written as;

3x² + 12x + 15 = 0

Take 3 common, we get;

3 (x² + 4x + 5) = 0

x² + 4x + 5 = 0

Factorize the equation by using Sridharacharya Formula;

x = - 4 ± √4² - 4*1*5 / 2*1

x = -4 ± √16 - 20 / 2

x = - 4 ± √-4 / 2

Since, √-1 = i

x = -4 ± 2i / 2                            

x = - 2 ± i

It gives two values of x as;

x = - 2 + i

And, x = - 2 - i

Hence, The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

Learn more about the quadratic equation visit:

brainly.com/question/24334139

#SPJ1

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Answer:

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Step-by-step explanation:

g(x + 1) = 5(x + 1)² - 3 = 5( x² + 2x + 1 ) - 3 = <em>5x² + 10x + 2</em>

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Find a formula for the described function. A rectangle has perimeter 16 m. Express the area A of the rectangle as a function of
Alex17521 [72]
Part A:

Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.

Let the length of the other side be x, then

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Thus, if the length of one of the side is x, the length of the other side is 8 - L.

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Part B:

To find the domain of A

Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.

Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.

Hence the domain of the area are the set of values between 0 and 8 not inclusive.

Therefore,

dom(Area)=0\ \textless \ L\ \textless \ 8 \ or \ (0, 8)
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