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Drupady [299]
8 months ago
15

Solve 3x^2=-12x-15 using a quadratic equation with complex solutions

Mathematics
1 answer:
adelina 88 [10]8 months ago
5 0

The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

What is Quadratic equation?

An algebraic equation of the second degree is called a quadratic equation.

Given that;

A quadratic equation is;

3x² = -12x - 15

Now, The equation is written as;

3x² + 12x + 15 = 0

Take 3 common, we get;

3 (x² + 4x + 5) = 0

x² + 4x + 5 = 0

Factorize the equation by using Sridharacharya Formula;

x = - 4 ± √4² - 4*1*5 / 2*1

x = -4 ± √16 - 20 / 2

x = - 4 ± √-4 / 2

Since, √-1 = i

x = -4 ± 2i / 2                            

x = - 2 ± i

It gives two values of x as;

x = - 2 + i

And, x = - 2 - i

Hence, The complex solution of a quadratic equation are (- 2 + i ) and

(- 2 - i ).

Learn more about the quadratic equation visit:

brainly.com/question/24334139

#SPJ1

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Answer:

C. (5x - 1)(x + 8)

Step-by-step explanation:

In a factoring problem by hand, the common steps to solve would be the "AM" method, or (Add-Multiply). Simply stated, finding what adds to the x-coeficient and what multiplies to the constant. In this case, what adds to 39(x) and what multiplies to 8. Just reading that, we can see that there aren't any numbers that can do that, so we have to improvise. Set up the problem equal to something that it can factor into:

  1. <em>Multiply the 5 and -8</em> = -40: <em>this is what we will factor</em>
  2. <em>The factors with add to 39 are 40 and -1</em>.
  3. <em>Set up the problem:</em>

5x^{2}+39x-8 = 5x^{2}+40x-x-8

Now, we can fo the math:

5x^{2} -8 = 5x^{2} -8

8(5x - 1) + x(5x - 1)

<em>Factor (5x - 1) from this:</em>

(5x - 1)(x + 8)

And we have our answer.

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Step-by-step explanation:

equation = 41100-(41100-36380)/(2011-2003)t

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4 and 5 is one 20/25

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