Question

A set of weights includes a 10 lb barbell and 8 pairs of weight plates. Each pairof plates weighs 20lbs. If x pairs of plates are added to the barbell, the total weight ofthe barbell and plates in points can be represented by (x) = 20x + 10.What is the range of the function for this situation?(A.2A)A {0,1,2,3,4,5,6,7,8}B {10, 30, 50, 70, 90, 110, 130, 150, 170}с {0,2,4,6,8}D {10,50, 90, 130, 170}

Answer 1

It is given that the weight of the barbel is given by:

$f(x)=20x+10$

It says that there are eight pair of weights so x can take values from 0 to 8 and f(x) can take the values as follows:

$\begin{gathered} x=0,f(x)=10 \\ x=1,f(x)=30 \\ x=2,f(x)=50 \\ x=3,f(x)=70 \\ x=4,f(x)=90 \\ x=5,f(x)=110 \\ x=6,f(x)=130 \\ x=7,f(x)=150 \\ x=8,f(x)=170 \end{gathered}$

So the range is:

$\mleft\lbrace10,30,50,70,90,110,130,150,170\mright\rbrace$

Option B is correct.