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Tomtit [17]
2 years ago
13

If y varies inversely with x and y = 5 when x = 4, which equation that relates x and y?

Mathematics
1 answer:
Bumek [7]2 years ago
7 0
X+4x-y5 is the wrong answer
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Can anyone help me please i dont understand this
Katena32 [7]

Answer:

try doing this for each quesion

so you see the negative? well negative means less than more. then use your signs and try to get it done reply if you still dont understand

Step-by-step explanation:

4 0
2 years ago
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CosA+cosB+cosC+cos(A+B+C)= cos(A+B).cos(B+C).cos(C+A)
RoseWind [281]

Answer:

cos (A+B+C)

Step-by-step explanation:

as A,B,C, are triangle we have A,B and C as 180

cost

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2 years ago
Hello please help me quick!
Ronch [10]

Answer:

Answer is A

Step-by-step explanation:

subtract 15 1/4 and 2 2/3

4 0
2 years ago
Could the inverse of a non-function be a function? Explain or give an example.
Kitty [74]

Answer:

The inverse of a non-function mapping is not necessarily a function.

For example, the inverse of the non-function mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form (a,\, b). The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.  

A mapping is a function if and only if for each possible input value x, at most one of the distinct pairs includes x\! as the value of first entry.

For example, the mapping \lbrace (0,\, 0),\, (1,\, 0) \rbrace is a function. However, the mapping \lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace isn't a function since more than one of the distinct pairs in this mapping include 1 as the value of the first entry.

The inverse of a mapping is obtained by interchanging the two entries of each of the pairs. For example, the inverse of the mapping \lbrace (a_{1},\, b_{1}),\, (a_{2},\, b_{2})\rbrace is the mapping \lbrace (b_{1},\, a_{1}),\, (b_{2},\, a_{2})\rbrace.

Consider mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!. This mapping isn't a function since the input value 0 is the first entry of more than one of the pairs.

Invert \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! as follows:

  • (0,\, 0) becomes (0,\, 0).
  • (0,\, 1) becomes (1,\, 0).
  • (1,\, 0) becomes (0,\, 1).
  • (1,\, 1) becomes (1,\, 1).

In other words, the inverse of the mapping \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! would be \lbrace (0,\, 0),\, (1,\, 0),\, (0,\, 1),\, (1,\, 1) \rbrace\!, which is the same as the original mapping. (Mappings are sets. There is no order between entries within a mapping.)

Thus, \lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\! is an example of a non-function mapping that is still not a function.

More generally, the inverse of non-trivial ellipses (a class of continuous non-function \mathbb{R} \to \mathbb{R} mappings, including circles) are also non-function mappings.

3 0
2 years ago
Currently you have two credit cards, h and i. card h has a balance of $1,186.44 and an interest rate of 14.74%, compounded annua
Dahasolnce [82]

Answer:

Step-by-step explanation:

Card I’s balance increased by $53.16 more than Card H’s balance.

5 0
3 years ago
Read 2 more answers
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