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RideAnS [48]
1 year ago
7

Write an equation based on these world problemKelsie wants to go play airsoft for $18.99 each hour (let that be h for hours) + $

5.00 one time fee for equipment. Let A = total cost of airsoft Jayson wants to go play paintball for $35 each hour (let that be h for hours) with no equipment fee. Let P = the total cost of paintball
Mathematics
1 answer:
Strike441 [17]1 year ago
8 0

Solution

Problem 1:

- Kelsie pays a one-time fee for the equipment of $5.00. This is a fixed cost that never changes and is paid just once.

- Kelsie pays $18.99 for each hour (h). This means that

For 1 hour, Kelsie pays $18.99 * 1 = $18.99

For 2 hours, Kelsie pays $18.99 * 2

For 3 hours, Kelsie pays $18.99 * 3

And so on...

- We can generalize this for h hours. That is,

For h hours, Kelsie pays $18.99 * h

- Thus, Kelsie pays $18.99h after h hours separate from the initial fee of $5.00.

- Thus, her total cost would be the addition of the flat fee of $5.00 and the cost of playing for h hours. That is:

\begin{gathered} Total\text{ Cost}(A)=18.99h+5 \\ where, \\ h=\text{ Number of hours elapsed} \end{gathered}

Problem 2:

- Jayson pays $35 per hour with no initial flat fee.

- Following the same logic as in the case of Kelsie, we can write the total cost incurred by Jayson after h hours is:

Total\text{ Cost\lparen P\rparen}=35h

Final Answer

The answers are:

Problem 1:

A=18.99h+5

Problem 2:

P=35h

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Factor the numbers.  What they have in common is the GCF.  

The GCF times everything leftover is the LCM.

6250: 5 × 5 × 5 × 5 × 5 × 2

2500: 5 × 5 × 5 × 5 × 2 × 2

What they have in common is the GCF:

6250: <u>5 × 5 × 5 × 5</u> × 5 × <u>2</u>

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GCF = 5 × 5 × 5 × 5 × 2 = 1250

GCF times everything leftover is the LCM:

6250: 5 × 5 × 5 × 5 × <u>5</u> × 2

2500: 5 × 5 × 5 × 5 × <u>2</u> × 2

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