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3 years ago

A rectangular garden 6 meters wide has a diagonal measuring 10 meters. Find the area of the rectangle.

Mathematics

1 answer:

uysha [10]3 years ago

4 0

Answer:

70.2 m²

Step-by-step explanation:

Area of rectangle = length × width

Pythagorean theorem.

a² + b² = c²

c² - a² = b²

a - side

b - side

c - diagonal

10² - 6² = b²

136 = b²

√136 = b

11.7 = b

11.7 × 6 = 70.2 m²

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The blueprint for a new swimming pool uses the scale 3/4 inch = 2 feet. If the actual dimensions of the pool will be 8 ft wide b

weeeeeb [17]

Answer:

The dimensions of the pool on the blueprint would be 3 in wide by 4.5 in long.

Step-by-step explanation:

First I turned 3/4 into a decimal, which would be 0.75. The I divided the dimensions of the pool by two. This way I could multiply the .75 by how many sets of two feet there were in the dimensions. Finally I multiplied 4 by .75 and I multiplied 6 by .75. That is how I found my answer.

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2 years ago

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Alexxandr [17]

The answer is 3/1 - the positive one

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3 years ago

HELP ME PLEASE!!!!!!!

kotegsom [21]

Answer:

1. (0,0) (3,1) (6,2)

2. proportinal

3. im so sorry but i cant see that one i really am sorry!

Step-by-step explanation:

i hope i helped brainliest?

3 0

3 years ago

Given the functions f(x) = 4x2 − 1, g(x) = x2 − 8x + 5, and h(x) = –3x2 − 12x + 1, rank them from least to greatest based on the

tangare [24]

Answer:

Option D) h(x), f(x), g(x)

Step-by-step explanation:

we know that

The axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex of the parabola

Part 1) we have

$f(x)=4x^{2} -1$

This is a vertical parabola open upward

The vertex is a minimum The vertex is the point (0,-1)

The x-coordinate of the vertex is 0

The axis of symmetry is x=0

Part 2) we have

$g(x)=x^{2}-8x+5$

This is a vertical parabola open upward

The vertex is a minimum

Convert the equation into vertex form

$g(x)-5=x^{2}-8x$

$g(x)-5+16=x^{2}-8x+16$

$g(x)+11=x^{2}-8x+16$

$g(x)+11=(x-4)^{2}$

$g(x)=(x-4)^{2}-11$

The vertex is the point (4,-11)

The x-coordinate of the vertex is 4

The axis of symmetry is x=4

Part 3) we have

$h(x)=-3x^{2}-12x+1$

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

$h(x)-1=-3x^{2}-12x$

$h(x)-1=-3(x^{2}+4x)$

$h(x)-1-12=-3(x^{2}+4x+4)$

$h(x)-13=-3(x+2)^{2}$

$h(x)=-3(x+2)^{2}+13$

The vertex is the point (-2,13)

The x-coordinate of the vertex is -2

The axis of symmetry is x=-2

Part 4) Rank their axis of symmetry from least to greatest

1) h(x) -----> axis of symmetry -2

2) f(x) -----> axis of symmetry 0

3) g(x) -----> axis of symmetry 4

h(x),f(x),g(x)

7 0

3 years ago

Does anyone know what to do. It’s for 6th grade math. The pencil part is a guess that I did.

HACTEHA [7]

Hullo! this looks complicated i know, but it's actually quite simple. if 2 bars feed 6 aliens, that means every number on top will be one third of the number on the bottom. so it would go like this (I'll go up to 9, and it should make sense from there)

2 | 2.3 | 2.6 | 3
------------------------
6 | 7 | 8 | 9

i hope this helped! if all else fails, just ask for help. it really does go a long way

5 0

3 years ago