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FromTheMoon [43]
2 years ago
11

(07.05 HC)In an experiment, sulfuric acid reacted with different volumes of sodium thiosulfate in water. A yellow precipitate wa

s formed during thereaction. A cross drawn at the base of each flask became gradually invisible due the formation of this yellow precipitate. The time taken for thecross to become invisible was recorded. A partial record of the experiment is shown.Experimental RecordFlask Volume of Volume of Volume of TimeH2SO4 Sodium Thiosulfate Water5 mL 50 mL10 mL 119 seconds5 mL 40 ml10 mL3 5 ml 30 ml120 mL4 15 ml 120 mL30 mLBased on your knowledge of factors that affect the rates of chemical reactions, predict the trend in the last column of the experimental record.Use complete sentences to explain the trend you predicted. You do not have to determine exact values for time; just describe the trend youwould expect (increase or decrease) and why it occurs.

Chemistry
2 answers:
kow [346]2 years ago
5 0
Increase is the correct answer i took the test!
strojnjashka [21]2 years ago
4 0

The rate of the reaction usually depends on the concentration of the reactants. We have to reactants in this reaction, sulfuric acid and sodium thiosulfate. Let's look at the values that were recorded.

The volume of sulfuric acid that is added is constant, but the volume of sodium thiosulfate is not. It decreases and the volume of water increases, so we are diluting the sodium thiosulfate. The concentration of one reactant is decreasing. So the rate of the reaction is also decreasing. Then the time that it takes for the cross to become invisible should increase.

Answer: the time should increase.

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As you move from bottom on the periodic table to the top shielding
masha68 [24]

Answer:

AS we move from bottom to top on periodic table shielding decreased.

Explanation:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction.

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As we move from bottom to top the energy level decreased because of decreased in electron thus shielding decreased and atomic size also decreased.

3 0
4 years ago
When it's noon in San Diego is it low tide, high tide or does it depend?
IrinaK [193]
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5 0
3 years ago
This element is named after the upper penisula?
Natasha_Volkova [10]
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5 0
3 years ago
Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
coldgirl [10]

Answer :

a. The oxidizing agent is: BH_4^-

b. The reducing agent is: ClO_3^-

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : BH_4^-\rightarrow H_2BO_3^-

Reduction : ClO_3^-\rightarrow Cl^-

Now balance oxygen atom on both side.

Oxidation : BH_4^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-  

Now balance hydrogen atom on both side.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-

Now balance the charge.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-

Reduction : ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-

Reduction : 4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-

The balanced chemical equation in acidic medium will be,

6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-

3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-

In the redox reaction, ClO_3^- act as oxidizing agent and BH_4^- act as an reducing agent.

7 0
3 years ago
radioisotope actinium 225 has half life of 10 days, I begin with 16 kg of this isotope, how much will remain after 40 days?
Igoryamba
N(t)=N_{0}(\frac{1}{2})^\frac{t}{\tau_{_\frac{1}{2}}}}\\\\
N_{0}=16kg\\
t=40days\\
\tau_{_\frac{1}{2}}}=10days\\\\\\
N(t)=16kg*(\frac{1}{2})^{\frac{40}{10}}=16kg*\frac{1}{16}=1kg
3 0
3 years ago
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