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SIZIF [17.4K]
2 years ago
9

What is the name of Pb(NO3)2? Explain how you determined the bond type and the steps you used to determine the naming convention

for the compound.
Chemistry
1 answer:
inysia [295]2 years ago
4 0

The name of Pb(NO3)2 of is Lead II trioxonitrate V

The bond which exist in is Lead II trioxonitrate V ( Pb(NO3)2 ) are both ionic and covalent bond

<h3>What is a compound?</h3>

A compound is a substance which contains two or more elements chemically combined together

So therefore, the name of Pb(NO3)2 of is Lead II trioxonitrate V

Learn more about a chemical compound:

brainly.com/question/26487468

#SPJ1

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The nucleus of an atom contains at least one<br> proton.<br> True or false
Svetllana [295]
The answer is falling
5 0
3 years ago
PLS
MrRissso [65]

Answer:

A decomposition reaction occurs when one reactant breaks down into two or more products. This can be represented by the general equation: AB → A + B. Examples of decomposition reactions include the breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.

8 0
3 years ago
Name different types of nutrients that our muscles need.
alexandr402 [8]

Answer:

Biotin. ...

Iron. ...

Vitamin C. ...

Selenium. ...

Omega 3. ...

Vitamin D. ...

Vitamin B12.

Explanation:

4 0
3 years ago
Read 2 more answers
In a neutral solution the concentration of _____. a. hydrogen ions is less than the concentration of hydroxide ions b. water mol
Georgia [21]

Answer:

In a neutral solution the concentration of hydrogen ions is equal to the concentration of hydroxide ions

Explanation:

When:

[H⁺] > [OH⁻]  the pH is acid, so the solution is practically acid.

When

[H⁺] < [OH⁻], the pH is basic, so the solution is practically basic

In neutral solutions:

[H⁺] = [OH⁻], so the pH is neutral (7)

pH > 7 → BASIC SOLUTIONS

pH < 7 → ACID SOLUTION

5 0
3 years ago
How do I solve the following word problem: The half-life of Phosphorus - 32 is 14.3 days. It is used to study a plant's use of f
BaLLatris [955]

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

We have the following equation representing the half-life decay:

A=A_o\times2^{(-\frac{t}{t_{half}})_{}_{}}

A is the resulting amount after t time

Ao is the initial amount = 50 mg

t= Elapsed time

t half is the half-life of the substance = 14.3 days

We replace the know values into the equation to have an exponential decay function for a 50mg sample

A=\text{ 50 }\times2^{\frac{-t}{14.3}}

That would be the answer for a)

To know the P-32 remaining after 84 days we have to replace this value in the equation:

\begin{gathered} A=\text{ 50 }\times2^{\frac{-84}{14.3}} \\ A=0.85\text{ mg} \end{gathered}

So, after 84 days the P-32 remaining will be 0.85 mg

4 0
1 year ago
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