Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

⇒ t = 8.7*10⁻⁴ sec.
hsjshekejeoehejeoejebenwkwuwbnwlwjdvrbrnfnfjkddjddmdmdndnfndmdkdjdjdjdjjdjdjdjdkdkdkdkdfkkdjdjdjdyremssjyehsmmamaajbshsjsbdbsksidhdbdbddddddddododododkdkdkdjdjdhddhhdvxbxbbxbxbxjdiegebeodhe
Answer:
all of these
Explanation:
As we know that, at the time of presentation we need to print copy of handouts for the audience of the presentation.
All three steps are necessary because.
A. There may be huge number of audience, so to save paper we place more than one slides per page
B. The flow of presentation must be same on handouts as on your presentation slides.
C. There should be a copy of handout for every person who is sitting in your presentation
Answer: RAM, random access memory is measured in GIGABYTES. Bsbdjdjdj