Answer:
This is a python program that counts the number of divisors of a given number and calculates the sum of the divisors.
Explanation:
The first line defines a function "sum_divisors" with an argument "n". The square root of the argument is converted to integer and assigned to the variable "x", then a for loop is used to iterate through the range 2 to the calculated nth number of divisors in the argument.The return keyword returns the sum value.
The function is called with several arguments and printed with the print function.
Answer:
nums = []
while True:
in = input()
if in:
nums.append(in)
else:
break
if nums:
avg = sum(nums) / len(nums)
for i in range(len(nums)):
if nums[i] == avg:
print(f"index: {i+1}")
print(nums[i])
else:
print(-1) # if there aren't any values in nums
Explanation:
Assuming that you are coding in Python 3x. The last 'else' statement is an edge case that you might want to consider, I don't know what you want to put there, but I'm just going to leave it as -1.
This is an easy answer sure in the back of your mind u knew it was b good luck :).
