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Alexxx [7]
2 years ago
12

? Question

Mathematics
1 answer:
Marizza181 [45]2 years ago
4 0

The equivalent expression for the expression (-5cd-4)(2cd²)² is - 20c³d⁵ - 16c²d⁴.

A finite combination of symbols that are well-formed in accordance with context-dependent principles is referred to as an expression or mathematical expression. Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Consider the expression,

(-5cd - 4)( 2cd²)²

Now let x = (-5cd - 4)( 2cd²)²,

Then,

x = (-5cd - 4)( 2cd²)²

x = ( - 5cd -4 ) × (2c)² × (d²)²

x = ( - 5cd - 4) × ( 4c² ) × d⁴

x = ( -5cd - 4 ) × 4c²d⁴

Using the distributive property,

x = ( - 5cd ) ×  ( 4c²d⁴ ) - 4 ×  4c²d⁴

x = - 20 × c³ × d⁵ - 16 ×  c²d⁴

x = - 20c³d⁵ - 16c²d⁴

Therefore, the equivalent expression of (-5cd-4)(2cd²)² is - 20c³d⁵ - 16c²d⁴.

Learn more about equivalent expression here:

brainly.com/question/14507158

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1 , 3 , 6 , 10 , 15
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First difference,

\Delta_{1} =  a_{2} - a_{1} = 3 - 1 = 2 = 1  + 1

Second difference,

\Delta_{2} =  a_{3} - a_{2} = 6 - 3 = 3 = 2 + 1

Third difference,

\Delta_{3} =  a_{4} - a_{3} = 10 - 6 = 4  = 3 + 1

And so on.

Assuming the pattern holds on, we see that

i-th difference,

\Delta_{i} =  a_{i + 1} - a_{i} = i + 1

\implies a_{i + 1} = a_{i}  +  i +  1

Then, nth term is,

\implies a_{n} = a_{n - 1} + n

= a_{n - 2}+ (n  + (n - 1))

= a_{n - 3} + (n + (n - 1) +(n - 2))

= a_{n - (n - 1)} + \sum \limits^{n - 2}_{k = 0}(n - k)

= a_1 + \sum \limits^{n - 2}_{k = 0}n-  \sum \limits^{n - 2}_{k = 0}k

= a_1 +n(n -2 + 1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +n(n -1 )-  \frac{1}{2} (n - 2)(n - 1)

= a_1 +(n -1 )(n-  \frac{1}{2} (n - 2))

= a_1 + \frac{1}{2} (n -1 )(2n- n  +  2)

= a_1 + \frac{1}{2} (n -1 )(n  +  2)

\implies a_{n} = 1 + \frac{1}{2} (n -1 )(n  +  2)

Now, the 21st term in the sequence is,

\implies a_{21} = 1 + \frac{1}{2} (21 -1 )(21  +  2)

= 1 + \frac{1}{2}  \times 20 \times 23

= 231

4 0
3 years ago
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