Question

%7B%20-%201%7D%20%7D%20" id="TexFormula1" title=" \frac{( {2a}^{3} )( {10a}^{5} )}{ {4a}^{ - 1} } " alt=" \frac{( {2a}^{3} )( {10a}^{5} )}{ {4a}^{ - 1} } " align="absmiddle" class="latex-formula">negative and zero exponents

Answer 1

$\begin{gathered} \frac{( {2a}^{3} )( {10a}^{5} )}{ {4a}^{ - 1} }=\frac{(2\cdot10)(a^3a^5)}{4}a \\ =\frac{20a^{3+5}a}{4} \\ =\frac{20}{4}a^8a \\ =5a^{8+1} \\ =5a^9 \end{gathered}$