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nirvana33 [79]
3 years ago
9

What is the exact value of x in the exponential equation 2^5x − 57 = 43?

Mathematics
1 answer:
katovenus [111]3 years ago
4 0
Start by getting the term with the exponent on one side
2^{5x}=100

take the log of both sides
log 2^{5x} =log100

There is a log rule that says we can bring down the exponent
5xlog2=log100

Solve for x
5x= \frac{log100}{log2}
5x=6.64

answer: x=1.33
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