Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.
Let AD=x, Since given AB=3
AD+DB=3
x+DB = 3
DB = 3-x
Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem
Since given AD=BC,let us plugin BC=x in above step.
6x=11
x=
Now we know AD=x= and given CD=√2.
Let us apply Pythagoras theorem for ΔACD
= 2.315cm
right
Answer:
90°
Step-by-step explanation:
Type of angle foremd= right
Measure = 40° + 50° = 90°
Type of angle foremd= right
Measure = 40° + 50° = 90°
Answer:
-1/18
Step-by-step explanation:
Let's multiply left and right by 3n:
2 = -12 * 3n =>
-36n = 2
now divide by -36:
n = 2/-36 = -1/18
Answer:
62
Step-by-step explanation:
