Answer:
v = 220 yd²
Step-by-step explanation:
Small portion
v = 5 * 4 * 3
v = 60 yd²
Large portion
v = 9 * 6 * 3
v = 162 yd²
Total
v = 60 + 162
v = 220 yd²
Answer:
1. 8x2 - 7x + 4x3 - 2-3x2 + 9x - 4 = 16+2x
Step-by-step explanation:
1. Multiply all the multiplication problems (should look like this --> 16-7x+12-2-6+9x-4)
2. Calculate the sum or difference (should end up looking like this --> 16-7x+9x) and then into this (16 +2x)
Bringing us to the answer → <u>16 + 2x!</u>
<u></u>
<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Answer:
f(g(2))=84
Step-by-step explanation:
Step one:
Given data
f(x)= x*2 +3
g(x) = 4x + 1
Step two
Let us find g(2) first then we proceed to find f(g(2))
g(2)=4(2) +1
g(2)=8+1
g(2)=9
Since g(2)=9
f(g(2))=x*2 +3
f(g(2))=9*2 +3
f(g(2))=81+3
f(g(2))=84
Answer:
x = 23
Step-by-step explanation:
Sum of 25 and x = 48
25 + x = 48
Subtract 25 from both sides
25 - 25 cancels out
48 - 25 = 23
We would be left with x = 23