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Levart [38]
3 years ago
13

Least to greatest 1/2, 2/5, 6/10

Mathematics
2 answers:
Elza [17]3 years ago
7 0
Answer : 2/5, 1/2, 6/10
Leviafan [203]3 years ago
6 0
Change all the fractions to decimal.

1/2=0.50
2/5=0.40
6/10=0.60

Least to greatest: 2/5, 1/2, 6/10

Hope this helped☺☺
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What is the greatest number that rounds to 60000
Archy [21]
The greatest number is 70000 and i know because im un fourth grade
7 0
3 years ago
If f(x)=2x-5 and g(x)=x^2-4x-8, find (f+g)(x).
viktelen [127]

f(x)=2x-5,\ g(x)=x^2-4x-8\\\\(f+g)(x)=f(x)+g(x)=(2x-5)+(x^2-4x-8)\\\\=2x-5+x^2-4x-8=x^2+(2x-4x)+(-5-8)=x^2-2x-13

8 0
3 years ago
Read 2 more answers
One quarter has a mass of 5.67 grams. Which is the mass of two rolls of quarters each containing 40 quarters?
Brilliant_brown [7]

9514 1404 393

Answer:

  453.6 g

Step-by-step explanation:

The mass of 80 quarters will be 80 times the mass of 1 quarter:

  80 × 5.67 g = 453.6 g

The mass of two rolls of quarters is 453.6 grams.

_____

<em>Additional comment</em>

That's about 1.0000 pounds.

4 0
3 years ago
A line contains (82,-96) and (87,-86) what is the slope of the line in simplified form
TiliK225 [7]

Here the change in x is +5 and that in y is +10 (from y= -96 to y= -86).  Thus, the slope, (change in y) / (change in x) is m = 10/5, or m = 2.

5 0
4 years ago
The following question has 2 parts. First, answer part A. Then, answer part B.
aalyn [17]

The fraction that represents the addition model shown above will be 53/100.

<h3>How to solve the fraction?</h3>

From the information given, a grid with 10 equal columns is shown with 5 shaded in. This will be expressed as 5/10.

Also, a second grid is shown, identical in size, containing 100 squares with 3 shaded in. This will be expressed as 3/100.

Therefore, the problem that represents the addition model shown above will be:

= 5/10 + 3/100

= 50/100 + 3/100

= 53/100

In this case, the answer given by Emma is incorrect as he added 5 to 3 and got 8/100.

Learn more about fractions on:

brainly.com/question/78672

4 0
2 years ago
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